Acceleration. If the line is linear on a velocity time graph, the acceleration does not change, meaning its 0
Answer:
30298514.82 m/s
Explanation:
M = Mass of star = 2×10³ kg
r = Radius of star = 5×10³ m
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
The object would be moving at a velocity of 30298514.82 m/s
1. 2 way radio
2. radio waves
3. communication
4. convert the voltage from a transmitter into a radio signal
5. signal strength refers to the transmitter power output
6. sorry, not so sure.. Though it might be the waves.
Answer:
Explanation:
Rate of change of pressure with respect to heigh
= k p ( given )
= k dh
Integrating on both sides
∫ = ∫ k dh
lnp = kh + c , c is a constant
when h = 1000 m , p = 89.1 k Pa
ln 89.1 = 1000 k + c -------------- (1)
when h = 0 , p = 103.6 k Pa
ln 103.6 = 0 x k + c
c = ln 103.6
Putting it in quation (1)
ln 89.1 = 1000 k + ln103.6
ln = 1000k
k =
= - .15 x 10⁻³
lnp = - .15 x 10⁻³ h + ln 103.6
when h = 3000
lnp = - .15 x 10⁻³ x 3000 + ln 103.6
= - .45 +4.64
= 4.2
p = 66.68 k Pa
b )
when h = 6358
lnp = - .15 x 10⁻³ x 6358 + ln 103.6
= - .9537 + 4.64
= 3.6863
39.9 k Pa.