Answer:
When a solution of silver nitrate is added to a solution of sodium chloride, the silver ions combine with the chloride ions to form a precipitate of silver chloride. The sodium and the nitrate ions are nonparticipating spectator ions. ... Like all equations, net ionic equations must be balanced.
Explanation:
source:
www.chem.uiuc.edu
<u>Answer:</u>
<em>To raise the pH of the solution to 3.10 we have to add 2.34 L of water.</em>
<u>Explanation:</u>
<em>Given that the pH of the solution of HCl in water is 2.5.</em> Here the solution’s pH is changing from 2.5 to 3.10 which means the acidic nature of the solution is decreasing here on dilution. ions contribute to a solution’s acidic nature and contribute to a solution’s basic nature.
The equation connecting the concentration of and pH of a solution is pH=
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<em>When the pH is </em>
<em>On dilution the concentration of a solution decreases and volume increases.</em>
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<em>Volume of water to be added </em>
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Answer:
Molarity = 0.24 mol/L
Explanation:
Given data:
Mass of NaNO3 = 25.4 g
Volume of solution = 1250 mL
Molarity = ?
Solution:
Molarity of solution is equal to the number of moles of solute divided by volume of solution in litter.
Formula:
Molarity = number of moles / volume in L
First of all we will convert the volume in litter.
1 L = 1000 mL
1250 / 1000 = 1.25 L
Now we calculate the moles of NaNO3 in present in 25.4 g.
Number of moles = mass / molar mass
Molar mass of NaNO3 = (23 + 14+ 16×3) = 85 g/mol
Number of moles = 25.4 g / 85 g/mol
Number of moles = 0.299 mol
Now we will calculate the molarity of solution
Molarity = number of moles / volume in L
Molarity = 0.299 mol / 1.25 L
Molarity = 0.24 mol/L
Explanation:
There are called inert gases, because they do not react with other elements.