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Molodets [167]
2 years ago
8

Pascal’s Law states that when pressure is applied from an outside source to a contained fluid, the force is

Chemistry
2 answers:
lions [1.4K]2 years ago
6 0

Answer:

a.....................

andrezito [222]2 years ago
5 0

Answer:

a

Explanation:

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How many moles of hcl are present in 40.0 ml of a 0.035 m solution?
Elden [556K]

Answer:

0.0014 moles is present in 40cm³ of 0.035M of HCl solution

Explanation:

Molarity = 0.035M

V = 40.0mL

1mL = 1cm³

V = 40cm³

0.035 moles = 1000cm³

X moles is present in 40cm³

X = (40 * 0.035) / 1000

X = 0.0014moles

0.0014 moles is present in 40cm³ of solution

8 0
3 years ago
Why does a beta particle have an atomic number of -1
Fudgin [204]
I cant entirely tell for now but an article on rodioactivity should solve the problem
6 0
3 years ago
In what two ways can an object possess energy?
-BARSIC- [3]

Explanation:

An object can possess energy in tow ways by it's motion or position

5 0
3 years ago
The temperature in mark’s town is 30 degrees Fahrenheit. The temperature in Vikki’s town is 82 degrees Fahrenheit. In both towns
allochka39001 [22]

Answer:

sorry don't know the answer but i really need the points sorry

Explanation:

7 0
3 years ago
A compound is 40.0% c, 6.70% h, and 53.3% o by mass. assume that we have a 100.-g sample of this compound. the molecular formula
atroni [7]
<span>When you have 100 g of compound, then based on the percentages given, there are 40.0 g C, 6.70 g H, and 53.3 g O. Convert those to moles:

</span>C: 40.0 g / 12.0 = 3.33 moles of C 
<span>H: 6.70 g / 1.01 = 6.63 moles of H </span>
<span>O: 53.3 / 16.0 = 3.33 moles of O 
</span>
<span>Dividing by the smallest (3.33), we get a C:H:O mole ratio of 1:2:1
</span>So, <span>The empirical formula is CH2O.
Now, </span><span>That formula has a molar mass of [12.0 + 2(1.0) + 16.0] = 30.0

And we are given it's molar mass is = 240

So, no. of units of CH2O = 240 / 30 = 8

</span><span>8 x CH2O = C8H16O8, and that is the molecular formula.
</span>
C_8H_{16}O_8
3 0
3 years ago
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