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3 years ago

Which groups of elements on the periodic table form metal ions that do not require roman numerals in their names?

Chemistry

1 answer:

Ivenika [448]3 years ago

8 0

Answer:

Aluminum, Zinc, Silver

Explanation:

Several exceptions apply to the Roman numeral assessment: Aluminum, Zinc, Silver. Although they belong to the transition metal category, these metals do not exist in one ion.

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In a sample of solid ba(no3)2 the ratio of barium ions to nitrate ions is

Nata [24]

I believe the ratio is 1:2

7 0

3 years ago

A student prepares two solutions as shown. The dots represent solute particles. The student wants to test the conductivity of ea

stealth61 [152]

Answer:

I think its D

Explanation:

It cant be B or C bc the solute particles arent changing. And its not A because the concentration isnt constant

3 0

2 years ago

what is the order of decreasing bond length for a C-C bond composed of the following molecular orbitals?I. sp^3 - sp^3II. sp^2 -

skelet666 [1.2K]

Answer:

The decreasing order of bond length in the carbon - carbon bonds will be:

$C-C>C=C>C\equiv C$

Explanation:

Bond length is defined as average distance between two nuclei of bonded atoms in a molecule.Bond length is inversely proportional to the number of bonds present between two atoms.

$\text{Bond length} \propto \frac{1}{\text{Number of bonds}}$ ...[1]

Bond energy is defied as amount of energy required to break apart the bond of 1 mole of molecule into their individual atom. Bond energy is directly proportional to the number of bonds present between two atoms.

$\text{Bond Energy} \propto \text{Number of bonds}$ ..[2]

From [1] and [2]:

$\text{Bond length} \propto \frac{1}{\text{Bond energy}}$

$C-C: sp_3$ hybridized

$C=C: sp_2$ hybridized

$C\equiv C: sp$ hybridized

Extent of overlapping of orbitals in these hybridization;

$C\equiv C> C=C > C-C$

Higher the overlapping of orbital more closer will be both atoms to each other and shorter will be the bond lenght.

So, the decreasing order of bond length in the carbon - carbon bonds will be:

$C-C>C=C>C\equiv C$

8 0

2 years ago

Calculate the number of nitrogen atoms in 240 g of ammonium nitrate?

gtnhenbr [62]

3.125 i believe is the answer

6 0

3 years ago

Read 2 more answers

Could you separate the sodium from the chlorine by crushing the salt crystals

Zigmanuir [339]

No, you cannot.

The distinction is made in the fact that the sodium and chlorine atoms are bonded chemically, while the crushing of the salt is a physical change. A physical change is one that does not have the ability to change the identity of the substance. Such changes include crushing, boiling, melting. In order to separate the chlorine and sodium atoms, you must make them undergo a chemical change, for example add the salt to sulfuric acid and make it react.

6 0

3 years ago