<span>13
Amino acids have a common structure where there is a carboxyl group at one end (CO2H) and a amino group at the other (NH2). There's also a side chain that's unique for every amino acid. When two amino acids are joined in producing a polypeptide, the carboxyl and amino groups are linked with the release of a water molecule.
So in this problem, you simply need to count the number of links, which will be 1 less than the number of amino acids in the chain. Hence, for a 14 amino acid chain, you need 13 links which produced 13 water molecules.</span>
<span>Ca3(PO4)2 + 3 H2SO4 = 3 CaSO4 + 2 H3PO4</span>
<span>Reaction type: double replacement
</span>
5.4*10^3 * 1.2*10^7.
5.4 * 1000 * 1.2 * 10000000
Multiply them = 64800000000
Answer:
You will have 19.9L of Cl2
Explanation:
We can solve this question using:
PV = nRT; V = nRT/P
<em>Where V is the volume of the gas</em>
<em>n the moles of Cl2</em>
<em>R is gas constant = 0.082atmL/molK</em>
<em>T is 273.15K assuming STP conditions</em>
<em>P is 1atm at STP</em>
The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:
63g * (1mol / 70.906g) = 0.8885 moles
Replacing:
V = 0.8885mol*0.082atmL/molK*273.15K/1atm
V = You will have 19.9L of Cl2
Answer: C9H11O3N
Explanation:
The percentage by mass of each element is divided by its relative atomic mass. The lowest ratio is now observed. Each ratio is now divided by this lowest ratio and approximated to whole numbers. All these are shown in detail in the image attached.
