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Taya2010 [7]
3 years ago
15

In what two ways can an object possess energy?

Chemistry
1 answer:
-BARSIC- [3]3 years ago
5 0

Explanation:

An object can possess energy in tow ways by it's motion or position

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The human body excretes nitrogen in the form of urea, NH₂CONH₂. The key step in its biochemical formation is the reaction of wat
Misha Larkins [42]

Mass perventage of nitrogen in urea, arginine, ornithine is   46.67%, 32.2%,21% respectively.

What is Mass perventage ?

Mass percentage is one way of representing the concentration of an element in a compound or a component in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100.

Molecular mass of urea (NH2CONH2) is= 2× (Atomic mass of N ) + 4 × (Atomic mass of H) + (Atomic mass of C) (Atomic mass of O) = 60

Mass percentage of N = Total mass of N atoms in the compoundMass of compound×100=2860×100=46.67%

chemical formula for arginine is C6H14N4O2

molar mass of C6H14N4O2=174g/mol

moles of N atoms in C6H14N4O2=4

mass of N atoms=14*4=56g

mass percent of N in C6H14N4O2=(56/174)*100=32.2%

the chemical formula for ornithine is C5H12N2O2

molar mass of C5H12N2O2=132g/mol

moles of N atoms in C5H12N2O2=2

mass of N atoms in C5H12N2O2=2*14=28

mass percent of N in C5H12N2O2=(28/132)*100=21%

To learn more about urea click on the link below:

brainly.com/question/17812875

#SPJ4

7 0
1 year ago
Food undergoes both physical and chemical changes during digestion. Which parts of the digestive process listed below is a physi
sergeinik [125]

Answer:

To answer your question use the code ICE on here to get your answer works every time for me hope this helps

3 0
3 years ago
The half life for the decay of carbon- is years. Suppose the activity due to the radioactive decay of the carbon- in a tiny samp
EleoNora [17]

The question is incomplete. The complete question is:

The half-life for the decay of carbon-14 is 5.73x10^3 years. Suppose the activity due to the radioactive decay of the carbon-14 in a tiny sample of an artifact made of woodfrom an archeological dig is measured to be 2.8x10^3 Bq. The activity in a similiar-sized sample of fresh wood is measured to be 3.0x10^3 Bq. Calculate the age of the artifact. Round your answer to 2 significant digits.

Answer:

570 years

Explanation:

The activity of the fresh sample is taken as the initial activity of the wood sample while the activity measured at a time t is the present activity of the wood artifact. The time taken for the wood to attain its current activity can be calculated from the formula shown in the image attached. The activity at a time t must always be less than the activity of a fresh wood sample. Detailed solution is found in the image attached.

6 0
3 years ago
Convert 8.876 × 10^12 m^2 to units of km^2.
Darya [45]

Answer:

8.876\times 10^{18}\ km^2

Explanation:

In this problem, we need to convert 8.876 \times 10^{12}\ m^2 to km².

We know that,

1 km = 1000 m

⇒ 1 km² = 10⁶ m²

So,

8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2

So, 8.876 \times 10^{12}\ m^2 is equal to 8.876\times 10^{18}\ km^2.

7 0
3 years ago
Half of the first 18 elements have an odd number of electrons, and half have an even number. Show why atoms of these elements ar
asambeis [7]

Answer:

Diamagnetism in atom occurs whenever two electrons in an orbital paired equalises with a total spin of 0.

Paramagnetism in atom occurs whenever at least one orbital of an atom has a net spin of electron. That is a paramagnetic electron is just an unpaired electron in the atom.

Here is a twist even if an atom have ten diamagnetic electrons, the presence of at least one paramagnetic electron, makes it to be considered as a paramagnetic atom.

Simply put paramagnetic elements are one that have unpaired electrons, whereas diamagnetic elements do have paired electron.

The atomic orbital and radius increases by gaining electron linearly so even electron numbered atoms are diamagnetic while the odd electron numbered atoms are paramagnetic.

Running through the first 18 elements one can observe that there is an alternative odd number of electrons and an even number proofing that that half of the first 18 elements shows paramagnetism and diamagnetism respectively.

Explanation:

3 0
3 years ago
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