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3 years ago

Your winter coat is an example of:

Chemistry

2 answers:

inessss [21]3 years ago

4 0

B. It keeps the warm inside

Pachacha [2.7K]3 years ago

3 0

B a good conductor that’s what I picked so should be right!

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Consider an ideal gas at 30 ∘C and 1.02 atm pressure. To get some idea how close these molecules are to each other, on the avera

Nastasia [14]

Answer: They are close to each other by 41.03 m^3

Explanation:

From Ideal gas equation, PV = nRT

Where n is negligible

R is gas constant = 8.314 J/mol.k

T = 30 + 273 = 303K

P = 1.02 * 103351.5 = 103351.5 Pascal

Then;

PV = RT

V = P/RT

V = 103351.5/(8.314*303)

V = 41.03m^3

8 0

3 years ago

Read 2 more answers

It is found that a gas undergoes a first-order decomposition reaction. If the rate constant for this reaction is 8.1 x 10-2 /min

kap26 [50]

Answer:

28.43 min

Explanation:

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Given that:

The rate constant, k = $8.1\times 10^{-2}$ min⁻¹

Initial concentration $[A_0]$ = 0.1 M

Final concentration $[A_t]$ = $1.0\times 10^{-2}$ M

Time = ?

Applying in the above equation, we get that:-

$1.0\times 10^{-2}=0.1e^{-8.1\times 10^{-2}\times t}$

$0.1e^{-8.1\times \:10^{-2}t}=10^{-2}$

$e^{-8.1\times \:10^{-2}t}=\frac{1}{10}$

$\ln \left(e^{-8.1\times \:10^{-2}t}\right)=\ln \left(\frac{1}{10}\right)$

$t=28.43\ min$

3 0

3 years ago

4. A student started with a 0.032 g sample of copper which he took through the series of reactions described in this experiment.

Elodia [21]

Answer:

$Y=48.6\%$

Explanation:

Hello,

In this case, we can consider the following chemical reaction for the oxidation of copper which only occurs at high temperatures:

$2Cu+O_2\rightarrow 2CuO$

In such a way, for 0.032 grams of copper, the following grams of copper (II) oxide (black product) are yielded:

$m_{CuO}=0.032gCu*\frac{1molCu}{63.546gCu} *\frac{2molCuO}{2molCu}*\frac{79.546gCuO}{1molCuO} =0.078gCuO$

Therefore, the percent yield is:

$Y=\frac{0.038g}{0.078g}*100\%\\ \\Y=48.6\%$

Best regards.

6 0

3 years ago

The density of a metal cube is 8 x103 kg/m3. Convert

Rom4ik [11]

Answer:

Explanation:

[peirod4

4 0

3 years ago

Please help me get the answer to bothe a and b

neonofarm [45]

Answer:

If a metal and metal solution react, the more reactive metal will displace the less reactive metal from solution. If the metal in solution you start with is formed from a more reactive metal than the metal to be added, no reaction will occur.

3 0

2 years ago