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zheka24 [161]
3 years ago
12

How many grams of solid sodium cyanide should be added to 1.50 L of a 0.175 M hydrocyanic acid solution to prepare a buffer with

a pH of 10.210?
Chemistry
1 answer:
marshall27 [118]3 years ago
7 0
I have -12 points thx a lot
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A major component of gasoline is octane (C8H18). When octane is burned in air, it chemically reacts with oxygen gas (O2) to prod
Olin [163]

Answer:

The answer is 6.25g.

Explanation:

First create your balanced equation. This will give you the stoich ratios needed to answer the question:

2C8H18 + 25O2 → 16CO2 + 18H2O

Remember, we need to work in terms of NUMBERS, but the question gives us MASS. Therefore the next step is to convert the mass of O2 into moles of O2 by dividing by the molar mass:

7.72 g / 16 g/mol = 0.482 mol

Now we can use the stoich ratio from the equation to determine how many moles of H2O are produced:

x mol H2O / 0.482 mol O2 = 18 H2O / 25 O2

x = 0.347 mol H2O

The question wants the mass of water, so convert moles back into mass by multiplying by the molar mass of water:

0.347 mol x 18 g/mol = 6.25g

8 0
3 years ago
Read 2 more answers
How does the average velocity of molecules in a high-temperature gas compare to the average velocity of molecules of the same ga
IrinaK [193]

Answer:lower temp molecules act slower so they come closer together and heated molecules are more spaced out that is why when you put an ice cube in a hot pan the ice melts and turns into a liquid due to heat the molecules space out

Explanation:

8 0
3 years ago
If 2.0 g of water at 0.00°c is to be vaporized, how much heat must be added to it? the specific heat of water is 1.0 cal/g·k, it
krok68 [10]
45 hope it helps hope you get a good grade

6 0
3 years ago
The Swedish chemist Karl Wilhellm was the first to produce chlorine in the lab
KiRa [710]

Answer:

Explanation:

Remark

Interesting que8stion. You have to figure out how many mols are present in each reactant. Since all periodic tables are different, I'm going to use rounded numbers. If it is too close, I will go further.

NaCl

Na = 23

Cl = 35.5

1 mol = 58.5 grams

given = 50.0 grams

Mols for the reaction = 50/58.5 = 0.855

H2SO4

H2       =    2*1        2

S          =   1 * 32   32

O4       =   4*16     64

1 mol  =               98   grams

mols  present = 50/98 = 0.510

MnO2

Mn     = 1 * 55    = 55

O2   =   2*16      = 32

1 mol =                  87 grams

mols available    = 50/87 = 0.5747

Discussion

Na Cl and H2SO4 both require 2 moles for every mol of Cl2 produces.

H2SO4  has 0.51 mols available for a reaction

NaCl has  0.855 moles available for a reaction

MnO2 has 0.575 moles available for a reaction.

Given those numbers 0.510 mols of H2SO4 will only produce 0.255 mols of chlorine and the rest will be reduced in a similar manner. H2SO4 is the limiting reagent (reactant).

In other words only 0.510 moles of NaCl will be used and 0.855 - 0.510 moles will be left over on the reactants side.

only 0.575 moles of MnO2 will be used and 0.065 moles will be left over.

The oddity in the result shows up because the balance numbers in the equation give a ratio of 2 to 1 for H2SO4 and NaCl The 2 belongs to the reactants and the 1 for the chlorine.

6 0
2 years ago
Consider the following chemical reaction:
kolezko [41]

<u>Answer:</u> The correct options are A and E

<u>Explanation:</u>

A chemical reaction is defined as the reaction in which two or more chemical substances react to form two or more different chemical substances.

A new substance (product) is formed in a chemical reaction when the bonds between the reactants are broken so that the new bonds between the products can be formed.

For a given chemical reaction:

HF+NaOH\rightarrow NaF+H_2O

Here,

HF is a covalent compound as sharing of electrons take place between hydrogen and fluorine atom

NaOH is an ionic compound as a complete transfer of electrons occurs from sodium to hydroxide.

Thus, to form the products, an ionic bond between sodium and hydroxide must be broken coupled with a covalent bond between hydrogen and fluorine.

Hence, the correct options are A and E

4 0
3 years ago
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