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3 years ago

Can any one help on this one

Chemistry

1 answer:

enyata [817]3 years ago

8 0

0.004382166 Make sure to round to the right amount of Sig Figs

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What is the mass in grams of 2.50 mol of ammonia vapor, NH3?

Crank

Molar mass:-

$\\ \tt\longmapsto 14+3(1)=17g/mol$

Now

$\\ \tt\longmapsto Given\:mass=No\;of\:moles\times Molar\;mass$

$\\ \tt\longmapsto Given\:mass=17(2.5)$

$\\ \tt\longmapsto Given\:mass=42.5g$

7 0

2 years ago

During the combustion of 2.00 g of coal, the temperature of 500 g of water inside the calorimeter increased from 25.0°c to 43.7°

pantera1 [17]

Answer is: 39,083kJ.
m(coal) = 2,00g.
m(water) = 500g.
ΔT = 43,7°C - 25°C = 18,7°C, <span>difference at temperatures.</span>
c(water) = 4,18 J/g·°C, <span>specific heat of water
</span>Q = m(water)·ΔT·c(water), heat of reaction.
Q = 500g·18,7°C·4,18J/g·°C.
Q = 39083J = 39,083kJ.

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2 years ago

If 3 moles of a compound use 12 J of energy in a reaction, what is the Hreaction in kJ/mol

igomit [66]

Answer:

$\Delta _RH=4x10^{-3}\frac{kJ}{mol}$

Explanation:

Hello,

In this case, the molar enthalpy of reaction is obtained by dividing the involved energy by the reacting moles:

$\Delta _RH=\frac{12J}{3mol} =4\frac{J}{mol}$

Thus, it is important to notice that the compound "uses" the energy, it means that it absorbs the energy, for that reason the sign is positive. Moreover, computing the result in kJ/mol we finally obtain:

$\Delta _RH=4\frac{J}{mol}*\frac{1kJ}{1000J} =4x10^{-3}\frac{kJ}{mol}$

Best regards.

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2 years ago

What kind of oxide is formed when a piece of sodium is dropped in the water

aleksley [76]

Answer:

Sodium oxide is the product

Explanation:

4Na+O2->2Na2O

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2 years ago

What is 5.73 moles in grams

Pani-rosa [81]

I calculated is and the answer is 1272.0600000000002.

I really don't know how to explain it

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2 years ago