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Nat2105 [25]
3 years ago
8

Which energy profile best shows that the enthalpy of formation of CS2 is 89.4 KJ/mol?

Chemistry
2 answers:
Anna11 [10]3 years ago
7 0

Answer:

Option C. Energy Profile D

Explanation:

Data obtained from the question include:

Enthalpy change ΔH = 89.4 KJ/mol.

Enthalpy change (ΔH) is simply defined as the difference between the heat of product (Hp) and the heat of reactant (Hr). Mathematically, it is expressed as:

Enthalpy change (ΔH) = Heat of product (Hp) – Heat of reactant (Hr)

ΔH = Hp – Hr

Note: If the enthalpy change (ΔH) is positive, it means that the product has a higher heat content than the reactant.

If the enthalpy change (ΔH) is negative, it means that the reactant has a higher heat content than the product.

Now, considering the question given, the enthalpy change (ΔH) is 89.4 KJ/mol and it is a positive number indicating that the heat content of the product is higher than the heat content of the reactant.

Therefore, Energy Profile D satisfy the enthalpy change (ΔH) for the formation of CS2 as it indicates that the heat content of product is higher than the heat content of the reactant.

VikaD [51]3 years ago
4 0
The correct answer is Option C
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Answer:

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Explanation:

Step 1: Data given

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Step 2: The balanced equation

HCl + NaHCO3 ⇔  NaCl + H2O + CO2

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moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles

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mass HCl = 0.032 * 36.46 g/mol= 1.17 grams

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