Answer:
Explanation:
For circuit in resonance , inductive and capacitive reactance should be equal. Since in the given circuit , these two are not equal, the circuit is not in resonance. It does not depend upon voltage provided.
option b is correct.
With this load, the fraction of the average power, put out by the source of emf, delivered to the load can be calculated as follows
Power delivered to resistor will be 2/3 rd of total power delivered by source because resistance has value twice that of reactance of capacitor. So the correct option is .7
option D ) is correct.
The answer is A.
A positive charge’s electric field pushes out.
Hope this helps! -Avenging
Approx. 983274984065823796374 meters away
Answer:
capacitance of the capacitor = 0.18 μ F
Explanation:
Area of the plate A = 0.063 m x 5.4 m = 0.3402 m²
distance between the plate d = 3.5 × 10–5 m
dielectric value for Teflon K = 2.1
capacitance of capacitor = ?
Formula for capacitance of parallel plate is as follows ,
(Where 
)
putting the values in the equation,
C = 
=0.18 μ F
Answer: exercise doing something you like. for example if you like dancing incorporate dancing in your workouts so you will be more likely to do it regularly
Explanation:
