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2 years ago

How does the heat transfer (a change in temperature) that occurs through ocean currents affect the land?

Physics

1 answer:

vlabodo [156]2 years ago

3 0

Answer:

Thus, ocean currents regulate global climate, helping to counteract the uneven distribution of solar radiation reaching Earth's surface. Without currents in the ocean, regional temperatures would be more extreme—super hot at the equator and frigid toward the poles—and much less of Earth's land would be habitable.

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ANSWER THE FOLLOWING QUESTION AND MAKE SURE TO GIVE A FULL DESCRIPTION TO HOW YOU GOT YOUR ANSWER (EX. make sure to use blank ru

vazorg [7]

Here is how I did it

6 0

3 years ago

The high-speed winds around a tornado can drive projectiles into trees, building walls, and even metal traffic signs. In a labor

Travka [436]

Answer:

F = 183.153 N

Explanation:

given,

mass of the toothpick = 0.12 g = 0.00012 kg

initial velocity = 227 m/s

final velocity = 0 m/s

penetration depth = 16 mm = 0.016 m

using the equation of motion

v² - u² = 2 a s

0 - u² = 2 a s

- 221² = 2 × a × 0.016

a = 1526281.25 m/s²

Force is equal to

F = m a

= 0.00012 × 1526281.25

F = 183.153 N

3 0

3 years ago

Select the correct answer.

soldi70 [24.7K]

Answer:

OD. The process of cutting down irrelevant information so only the information that is useful for particular purpose remains

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2 years ago

A thin, light wire 75.2 cm long having a circular cross section 0.560 mm in diameter has a 25.2 kg weight attached to it, causin

blsea [12.9K]

Answer:

The stress is calculated as $1.003\times 10^{9}\ Pa$

Solution:

As per the question:

Length of the wire, l = 75.2 cm = 0.752 m

Diameter of the circular cross-section, d = 0.560 mm = $0.560\times 10^{- 3}\ m$

Mass of the weight attached, m = 25.2 kg

Elongation in the wire, $\Delta l = 1.10\ mm = 1.10\times 10^{- 3}\ m$

Now,

The stress in the wire is given by:

$Stress,\ \sigma = \frac{Force,\ F}{Area,\ A}$ (1)

Now,

Force is due to the weight of the attached weight:

F = mg = $25.2\times 9.8 = 246.96\ N$

Cross sectional Area, A = $\pi (\frac{d}{2})^{2} = \pi (\frac{0.560\times 10^{- 3}}{2})^{2} = 2.46\times 10^{- 7}\ m^{2}$

Using these values in eqn (1):

$\sigma = \frac{246.96}{2.46\times 10^{- 7}} = 1.003\times 10^{9}\ Pa$

8 0

2 years ago

A satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther a

irinina [24]

The speed of the second satellite is less than the speed of the first satellite.

<h3>What is speed?</h3>

The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.

Given is a satellite is in a circular orbit around a planet. A second satellite is placed in a different circular orbit that is farther away from the same planet.

When the distance from the center of the orbit increases, the time to complete the orbit will be greater.

Thus, the speed of the second satellite is less than the speed of the first satellite.

Learn more about speed.

brainly.com/question/7359669

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3 0

1 year ago