Answer:
2 half lives.
Explanation:
Suppose there are 100g of parent isotope at the start.
After 1 half-life there will be 50g of parent and 50g of daughter isotope.
After another half life there is 25 g of parent and 75g of daughter isotope.
Answer:
Carbon Monoxide / Carbon Dioxide / Sulfur and Nitrogen Dioxide
Explanation:
The grams of ethane present in a sample containing 0.4271 mole is 12.84 g
<h3>Description of mole </h3>
The mole of a substance is related to it's mass and molar mass according to the following equation
Mole = mass / molar mass
With the above formula, we can obtain the mass of ethane. Details below
<h3>How to determine the mass of ethane</h3>
The following data were obtained from the question:
- Mole of ethane = 0.4271 mole
- Molar mass of ethane = 30.067 g/mol
- Mass of ethane =?
The mass of ethane present in the sample can be obtained as follow:
Mole = mass / molar mass
Cross multiply
Mass = mole × molar mass
Mass of ethane = 0.4271 × 30.067
Mass of ethane = 12.84 g
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