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Pavel [41]
3 years ago
5

What is the [H+] and [OH-] of a 3.5 M HCIO3 solution?

Chemistry
1 answer:
levacccp [35]3 years ago
3 0

Answer: H+ ia helyuim

explinanation: Hope this helped!!

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Pls help im very lost on this
Vedmedyk [2.9K]
Metals is found on the left side of the table and the nonmetals is on the top right.
4 0
3 years ago
Read 2 more answers
Many common liquids have boiling points that are less than 110°C, whereas most metals are solids at room temperature and have mu
Semmy [17]

Answer:

1. 315.4 K

2. 1560 °C

Explanation:

To convert from celsius to Kelvin, the following formula can be used:

T(K) = T(°C) + 273

Where:

T(K) => Temperature in Kelvin

T(°C) => Temperature in degree celsius

1. Determination of the temperature in Kelvin.

Temperature (T) in °C = 42.4 °C.

Temperature (T) in K =?

T(K) = T(°C) + 273

T(K) = 42.4 °C + 273

T(K) = 315.4 K

2. Determination of the temperature in degree Celsius.

Temperature (T) in K = 1833 K

Temperature (T) in °C =?

T(K) = T(°C) + 273

1833 = T(°C) + 273

Collect like terms

T(°C) = 1833 – 273

T(°C) = 1560 °C

7 0
3 years ago
How much does 2.17 mole of CU weigh?
Sergio [31]

Answer:

137.9035 g

Explanation:

1 mole of copper in grams is 63.55 g

2.17 mole of Cu weighs 137.9035 g (63.55x2.17)

6 0
3 years ago
A typical aspirin tablet contains 327 mg of acetylsalicylic acid, HC9H7O4. Calculate the pH of a solution that is prepared by di
yawa3891 [41]

Answer:

2.8

Explanation:

First, we will calculate the molarity of the acetylsalicylic acid solution.

M = mass of solute (g) / molar mass of solute × volume of solution (L)

M = 0.327 g / 180.158 g/mol × 0.237 L

M = 7.66 × 10⁻³ M

For a weak acid such as acetylsalicylic acid, we can find the concentration of H⁺ using the following expression.

[H⁺] = √(Ca × Ka)

where,

Ca: concentration of the acid

Ka: acid dissociation constant

[H⁺] = √(7.66 × 10⁻³ × 3.3 × 10⁻⁴)

[H⁺] = 1.6 × 10⁻³ M

The pH is:

pH = -log [H⁺]

pH = -log 1.6 × 10⁻³ = 2.8

6 0
3 years ago
Find the boiling point?<br> 100. g of C2H6O2 dissolved in 200 g of H2O?
aleksklad [387]

Answer:

The correct answer is 104.13ºC

Explanation:

When a solute is added to a solvent, the boiling point of the solvent (Tb) increases. That is a colligative property. The increment in Tb (ΔTb)  is given by the following expression:

ΔTb = Tb - Tbº= Kb x m

Where Tb and Tbº are the boiling points of the solvent in solution and pure, respectively; Kb is a constant and m is the molality of the solution.

In this problem, the solvent is water (H₂O). It is well known that water has a boiling point of 100ºC (Tb). The value of Kb for water is 0.512ºC/m. So, we have to calculate the molality of the solution (m):

m = moles of solute/Kg solvent

The solute is C₂H₆O₂ and we have to calculate the number of moles of this component by dividing the mass into the molecular weight (Mw):

Mw(C₂H₆O₂)= (2 x 12 g/mol) + (6 x 1 g/mol) + (2 x 16 g/mol)= 62 g/mol

⇒ moles of C₂H₆O₂ = mass/Mw = 100 g/(62 g/mol) = 1.613 moles

Now, we need the mass of solvent (H₂O) in kilograms, so we divide the grams into 1000:

200 g x 1 kg/1000 g = 0.2 kg

Finally, we calculate the molality as follows:

m = 1.613 moles of C₂H₆O₂/0.2 kg = 8.06 moles/kg = 8.06 m

The increment in the boiling point will be:

ΔTb = Kb x m = 0.512ºC/m x 8.06 m = 4.13ºC

So, the boiling point of pure water (Tbº=100ºC) will increase in 4.13ºC:

Tb= 100ºC+4.12ºC= 104.13ºC

5 0
3 years ago
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