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2 years ago

M=1/2 and the y-intercept is (0, -5)

Mathematics

1 answer:

Black_prince [1.1K]2 years ago

7 0

Answer: plug in y=mx + b

Step-by-step explanation:

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Is it impossible to raise the number to the power of to and get a number less than the original number

finlep [7]

No (unless you're talking about a whole number), for example...
0.2^2 = 0.04

8 0

3 years ago

P (6,6) y=2/3x

matrenka [14]

Answer:

$y = -\frac{3}{2}x+15$

Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

$y = \frac{2}{3}x$

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

$y = \frac{2}{3}x$

Now, we compare the given equation by standard form $y = mx +c$

So, slope of the line $m_{1} = \frac{2}{3}$ , and

y-intercept $c=0$

We know that the slope of the perpendicular line $m_{1}\times m_{2} = -1$

$m_{2}=-\frac{1}{m_{1}}$

$m_{2}=-\frac{1}{\frac{2}{3} }$

$m_{2}=-\frac{3}{2}$

So, the slope of the perpendicular line $m_{2}=-\frac{3}{2}$

From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

$y=mx+c$

Substitute point $P(x_{1}, y_{1})=P(6, 6)$ and $m = m_{2}=-\frac{3}{2}$

$6=-\frac{3}{2}\times 6 +c$

$6=-3\times 3 +c$

$c=6+9$

$c=15$

So, the y-intercept of the perpendicular line $c=15$

Using point slope formula.

$y=mx+c$

Substitute $m = m_{2}=-\frac{3}{2}$ and $c=15$ in above equation.

$y = -\frac{3}{2}x+15$

Therefore: the equation of the perpendicular line $y = -\frac{3}{2}x+15$

8 0

3 years ago

????????????????????

Svet_ta [14]

#2- yes because both can be divided or multiplied for example 3 and 9, u can multiply 3x3 to get 9 since the dilation is 3 then yes it is similar triangles

4 0

3 years ago

What is 8.275 rounded to the nearest ounce?

Crank

Answer:

8.0

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find f(x) and g(x) so the function can be expressed as y = f(g(x)).

DanielleElmas [232]

$\bf \begin{cases}
f(x)=\cfrac{8}{x}+4\\\\
g(x)=x^2
\end{cases}\qquad f(\ g(x)\ )=\cfrac{8}{\underline{g(x)}}+4\implies f(\ g(x)\ )=\cfrac{8}{\underline{x^2}}+4$

3 0

3 years ago