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2 years ago

M=1/2 and the y-intercept is (0, -5)

Mathematics

1 answer:

Black_prince [1.1K]2 years ago

7 0

Answer: plug in y=mx + b

Step-by-step explanation:

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Elena and Noah used different methods to compute 0.23 x 1.5. Both calculations were correct. Analyze the 2 methods.

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2 years ago

Some one please help!

nasty-shy [4]

Answer:

The answers are 23, 9,200 and 26, 10,400

Step-by-step explanation:

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2 years ago

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Tristan is comparing two number patterns based on the information below. Both patterns start with the number 1. Pattern A follow

Oksana_A [137]

Answer:

Pattern B gets larger faster.

Step-by-step explanation:

Pattern A: 1, 4, 7, 10, 13

Pattern B: 1, 5, 9, 13, 17

The terms of pattern B are larger than those of Pattern A by 1 less than the number of the term. (Term 5 of Pattern B is 4 more than term 5 of Pattern A, for example.)

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2 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

2 years ago

-2x^2+4x-1 from 6x^2+3x-9

kirza4 [7]

Answer:

$8{x}^{2} - x - 8$

Step-by-step explanation:

We want to subtract

$- 2 {x}^{2} + 4x - 1$

from

$6 {x}^{2} + 3x - 9$

We set up the subtracttion problem to get:

$6 {x}^{2} + 3x - 9 - ( - 2 {x}^{2} + 4x - 1)$

We expand the parenthesis to get:

$6 {x}^{2} + 3x - 9 + 2 {x}^{2} - 4x + 1$

Group similar terms:

$6 {x}^{2} + 2 {x}^{2} + 3x- 4x + 1 - 9$

We simplify to get:

$8{x}^{2} - x - 8$

4 0

3 years ago