2 years ago

How many moles are there in 3.9 grams of potassium

Chemistry

2 answers:

Maksim231197 [3]2 years ago

8 0

Answer:

0.0997 mol K

Explanation:

First of all, the picture and your question do NOT match so I will solve for what you are asking for.

3.9g x 1 mol/39.10 g = 0.0997 mol K

The 39.10 grams is the atomic mass of potassium

zimovet [89]2 years ago

7 0

1.77 so A. I don’t need to explain this just helping out haha

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Answer : The number of moles of gas present in container are 1.697 mole.

Explanation :

Using ideal gas equation,

$PV=nRT$

where,

P = pressure of gas = 74 mmHg = 0.097 atm

conversion used : (1 atm = 760 mmHg)

V = volume of gas = 500.0 L

T = temperature of gas = $75^oC=75+273=348K$

n = number of moles of gas = ?

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get the number of moles of gas in the container.

$(0.097atm)\times (500.0L)=n\times (0.0821L.atm/mole.K)\times (348K)$

$n=1.697mole$

Therefore, the number of moles of gas present in container are 1.697 mole.

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