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nikdorinn [45]
3 years ago
13

In the real world, orbiting objects such as satellites and stations do not need to be constantly accelerating. What is different

about the real world satellites and the theoretical satellites we are discussing here?
Physics
1 answer:
JulijaS [17]3 years ago
8 0
What do you mean by theoretical satellites? When you mean real world satellites are you talking about the ones in space because I'm not sure what else you talking about.. I wanna help but could you explain plz??
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If an object is dropped from a tall building and hits the ground 3.0 s later, how tall is the building?
allsm [11]
D = 1/2 g t^2. It works out to 44.1 meters.
6 0
3 years ago
The volume of a piece of metal of a mass 6 gram is 15cm3. What is the density of the metal piece?
torisob [31]

Answer:

0.4 g/cm^3

Explanation:

The density of an object can be found using the following formula.

d= m/v

where m is the mass and v is the volume.

The mass of the metal is 6 grams and the volume is 15 centimeters^3

m=6 g

v= 15 cm^3

Substitute these into the formula.

d= 6 g/ 15 cm^3

Divide 6 g by 15 cm^3 (6/15=0.4)

d= 0.4 g/ cm^3

The density of the metal is 0.4 grams per cubic centimeter.

4 0
3 years ago
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What is The common value for the speed of light in a vacuum
Talja [164]
The most common value for the speed of light is 3*10^8 meters/second.

A more accurate number is <span>299 792 458 m/second, but that number is hardly ever used.</span>
4 0
4 years ago
A resistor, inductor, and a battery are arranged in a circuit. The circuit has an inductance of L = 1 H and a resistance of 1.4
shtirl [24]

Answer:

\tau \approx 7.14 \times 10^{-4}s \approx0.714ms

Explanation:

In a LC circuit The time constant τ is the time necessary for 60% of the total current (maximum current), pass through the inductor after a direct voltage source has been connected to it. The time constant can be calculated as follows:

\tau =\frac{L}{R}

Therefore, the time needed for the current to reach a fraction f = 0.6(60%) of its maximum value is:

\tau =\frac{1}{1.4\times 10^{3}} =7.142857143 \times 10^{-4} \approx7.14 \times 10^{-4}s

8 0
4 years ago
Two pebbles are dropped into a pool of water as shown. If a new wave with a
Kazeer [188]

Answer:

Constructive interference

Explanation:

3 0
3 years ago
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