Can you be fluid overload and dehydrated at the same time

A man can lift a mass of 200kg onThe surface of the earth. what is the amount of mass he can lift on the surface of the moon?

Arlecino [84]

Answer:

1,211.1 kg.

Explanation:

the force of gravity is less on the moon than on earth, so if the man can lift 200kg on earth, he could lift a greater amount on the moon because there is less resistance from gravity.

To know the amount of mass he can lift on the moon, we first need to know the amount of weight that is equivalent to those 200kg here on earth. This because the weight of the object is equal to the force that must be applied to lift it, and that force is applied by the man and it will be the same here and on the moon.

We calculate weight using the formula:

$w=mg$

where $w$ is the weight of the object (the force with which the earth attracts the object) $m$ is the mass and g the acceleration of gravity.

so

$w=200g$

for earth the acceleration due to gravity is: $g=9.81m/s^2$

thus:

$w=(200kg)(9.81m/s^2)\\w=1962N$

now we use this value to calculate the mass he can lift on the moon, since for the moon $g=1.62m/s^2$ .

we use the same equation, w =mg substituting w = 1962N and $g=1.62m/s^2$ :

$w=mg\\\\1962N=m(1.62m/s^2)\\\\m=\frac{1962N}{1.62m/s^2}\\\\ m=1,211.1kg$

he can lift 1,211.1 kg.

You can also find the result using the approximate value of the acceleration of gravity on the moon as g/6, where g is the acceleration on earth.

8 0

4 years ago

The change in color when acetone is placed on the wing is due to the difference between the indices of refraction of acetone and

Rasek [7]

Answer:

Option B and Option C

Explanation:

As we know that the wavelength of light is dependent on its speed. In fact the wavelength of light is directly proportional to the speed of the light. If the speed increases, the wavelength will also increase. While moving from air to acetone the speed of light reduces, and hence the wavelength reduces.

Wavelength is inversely proportional to the frequency. In acetone, the wavelength of light reduces, thus the frequency must increase and it should be higher than the frequency of light in air.

Option B and C are correct

3 0

4 years ago

Water flows through a horizontal coil heated from the outside by high temperature flue gases. as it passes through the coil wate

-BARSIC- [3]

For the steady flow process, the first law is written like

DH + Du2/2 + gDz = Q + Ws

since there is no shaft work, Ws = 0

and flow is horizontal, Dz = 0

Therefore,

DH + Du2/2 = Q

substituting for the quantities,

(2726.5 - 334.9) x 1000 + (200^2 - 3^2)/2 = Q (in terms of J/kg)

Q = 2411.1 kJ/kg

Heat transferred through the coil per unit mass of water = 2411.1 kJ

4 0

4 years ago

A catapult with a radial arm 3.81 m long accelerates a ball of mass 18.2 kg through a quarter circle. The ball leaves the appara

saw5 [17]

Answer:

(a) $\alpha = 53.73 m/s^2$

(b) I =428 $kgm^2$

(c) $\tau = 428 \times 53.73 = 22996 .44Nm$

Explanation:

GIVEN

mass = 18.2 kg

radial arm length = 3.81 m

velocity = 49.8 m/s

mass of arm = 22.6 kg

we know using relation between linear velocity and angular velocity

$\omega = \frac{v}{l}$

$\omega = \frac{49.8}{3.81} \\\omega = 12.99 rad/s$

for angular acceleration, use the following equation.

$\omega _{f}^2 = \omega_{i}^2+2\alpha\theta$

since $\omega _{i} = 0$

here for one circle is 2 π radians. therefore for one quarter of a circle is π/2 radians

so for one quarter $\theta = \frac{\pi }{2}$

$(12.99)^2 = 2\alpha(\frac{\pi }{2})$

on solving

$\alpha = \frac{168.74}{\pi }\\\alpha = 53.73 m/s^2$

(b)

For the catapult,

moment of inertia

$I = \frac{1}{2}MR^2$

$I = \frac{1}{2} \times 22.6\times 3.81 \times 3.81\I = 164kg m^2$

For the ball,

$I = MR^2$

$I = 18.2 \times 14.51$

$I = 264 kgm^2$

so total moment of inertia = 428 $kgm^2$

(c)

$\tau = I\alpha$

$\tau = 428 \times 53.73 = 22996 .44Nm$

3 0

4 years ago

How do I find the x and y components and the resultant force?

Dafna11 [192]

Explanation:

1) the diagonal force times the sine of the angle it makes will give you the vertical component or y component . use this to get the vertical components of all the diagonal forces . add all the vertical components as well as the vertical forces together

2) the diagonal force times the cosine of the angle it makes gives the horizontal component or x component. do this to get the x component of all the diagonal forces.

add all the x components as well as the horizontal forces together to get the final x component

3)using the triangle of vectors, the resultant force is calculated

sum of y component = 3.2N

sum of x component= 5.7N

resultant force = 6.5N

3 0

3 years ago