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lorasvet [3.4K]
4 years ago
15

Can you be fluid overload and dehydrated at the same time

Physics
1 answer:
STALIN [3.7K]4 years ago
5 0
.................yes...................
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A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J. What is the mass of the soccer ball
Savatey [412]
A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J.The mass of the soccer ball is 0.4 kgs. This answer is derived from the formula K=1/2 MV^2.So velocity and kinetic energy are given from that mass of the ball is calculated.By substituting the values 500=1/2*M*50*50 which gives M=0.4 Kgs.<span>
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4 0
3 years ago
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A nonconducting spherical shell, with an inner radius of 4 cm and an outer radius of 6 cm, has charge spread non uniformly throu
Aloiza [94]
In other words a infinitesimal segment dV caries the charge 
<span>dQ = ρ dV </span>

<span>Let dV be a spherical shell between between r and (r + dr): </span>
<span>dV = (4π/3)·( (r + dr)² - r³ ) </span>
<span>= (4π/3)·( r³ + 3·r²·dr + 3·r·(dr)² + /dr)³ - r³ ) </span>
<span>= (4π/3)·( 3·r²·dr + 3·r·(dr)² + /dr)³ ) </span>
<span>drop higher order terms </span>
<span>= 4·π·r²·dr </span>

<span>To get total charge integrate over the whole volume of your object, i.e. </span>
<span>from ri to ra: </span>
<span>Q = ∫ dQ = ∫ ρ dV </span>
<span>= ∫ri→ra { (b/r)·4·π·r² } dr </span>
<span>= ∫ri→ra { 4·π·b·r } dr </span>
<span>= 2·π·b·( ra² - ri² ) </span>

<span>With given parameters: </span>
<span>Q = 2·π · 3µC/m²·( (6cm)² - (4cm)² ) </span>
<span>= 2·π · 3×10⁻⁶C/m²·( (6×10⁻²m)² - (4×10⁻²m)² ) </span>
<span>= 3.77×10⁻⁸C </span>
<span>= 37.7nC</span>
6 0
3 years ago
Which one of the following is not equivalent to 2.50 miles?
lisabon 2012 [21]

Answer:

Choice C is not equivalent to 2.50 miles.

Explanation:

The given data is now converted into feet, inches, kilometers, yards and centimeters:

mi - ft

x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi} \right)

x = 13200\,ft

x = 1.320\times 10^{4}\,ft (Choice A)

mi - in

x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi} \right)\cdot \left(12\,\frac{in}{ft} \right)

x = 158400\,in

x = 1.584\times 10^{5} (Choice B)

mi - km

x = (2.50\,mi)\cdot \left(1.61\,\frac{km}{mi} \right)

x = 4.025\,km (Different from Choice C)

mi - yd

x = (2.50\,mi)\cdot \left(5280\,\frac{ft}{mi}\right) \cdot \left(\frac{1}{3}\,\frac{yd}{ft}  \right)

x = 4400\,yd

x = 4.40\times 10^{3}\,yd (Choice D)

mi - cm

x = (2.50\,mi)\cdot \left(1.61\,\frac{km}{mi} \right)\cdot \left(100000\,\frac{cm}{km}\right)

x = 402500\,cm

x = 4.025\times 10^{5}\,cm (Choice E)

Choice C is not equivalent to 2.50 miles.

6 0
4 years ago
Light cannot escape the intense gravitational pull of a _____.
natima [27]
Black hole 
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3 0
3 years ago
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Which of the following statements is accurate
natta225 [31]
I would say that B seems more accurate because rhythm and tone seems like a poem
8 0
3 years ago
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