This causes reverse faults<span>, which are the reverse of </span>normal faults<span>, because in this case, the hanging wall slides upward relative to the footwall. Shear </span>stress<span> is when rock slabs slide past each other horizontally. There is no vertical movement of either the hanging wall or footwall, and we get a strike-slip </span>fault<span>.</span>
<span>So we want to know which statement is true for the body of mass m=2000kg that is lifted to a height of h=15m in t=15 s. Lets calculate each of the following: Gravity force on the body is F=m*g=2000*9.81=19620 N so a is FALSE. Potential energy of the body when it is lifted to the height of 15 m is Ep=m*g*h=2000*9.81*15=294300 J so b is FALSE. Work to lift the body is: W=Fg*h=2000*9.81*15= Ep=294300 J so c is FALSE. Power P=W/t=294300/15=19620 W So d is TRUE. </span>
Answer:
The total charge Q of the sphere is
.
Explanation:
Given that,
Radius = 5 cm
Charge density 
We need to calculate the total charge Q of the sphere
Using formula of charge

Where,
= charge density
V = volume
Put the value into the formula

Put the value into the formula


Hence, The total charge Q of the sphere is
.
<span>A spatial pattern arranges main points according to physical direction or location.</span>