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3 years ago

Short note on dung fertilization

Chemistry

2 answers:

bogdanovich [222]3 years ago

7 0

Answer:

Most manure consists of animal feces; other sources include compost and green manure. Manures contribute to the fertility of soil by adding organic matter and nutrients, such as nitrogen, that are utilised by bacteria, fungi and other organisms in the soil.

Explanation:

Hope it is helpful....

mestny [16]3 years ago

6 0

Answer:

Animal manure, such as chicken manure and cow dung, has been used for centuries as a fertilizer for farming. It can improve the soil structure (aggregation) so that the soil holds more nutrients and water, and therefore becomes more fertile. ... Manure is also commercially composted and bagged and sold as a soil amendment.

Explanation:

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Determine the molality of ions in a solution formed by dissolving 0.187 moles of NaCl in 456 grams of water. The density of the

PSYCHO15rus [73]

Answer:

Molality Ions Na⁺ = 0.410 m

Molality Ions Cl⁻ = 0.410 m

Total ion molality = 0.820 m

Explanation:

Molality (m) is defined as moles of solute that are dissolved in 1000g (1kg) of solvent. In this case, the molality of the ions is requested, so it should be borne in mind that when the NaCl salt dissolves in the water, it dissociates forming ions as follows:

NaCl ⇒Na⁺ (aq) + Cl⁻ (aq)

Therefore, for each mole of salt that dissolves, you will have 1 mole of Na⁺ and 1 mole of Cl⁻

Knowing the amount of initial solute moles and the mass of water, we proceed to perform the calculations for each ion:

Ions Na⁺

456 g of H₂O ____ 0.187 mol Na⁺

1000 g of H₂O ____ X = 0.410 m

Calculation: 1000 g x 0.187 mol / 456 g = 0.410 mol

Ions Cl⁻

456 g of H₂O ____ 0.187 mol Cl⁻

1000 g of H₂O ____ X = 0.410 m

Calculation: 1000 g x 0.187 mol / 456 g = 0.410 m

If both results are added, the total molality of the ions will be obeyed:

0.410 m + 0.410 m = 0.820 m

This means that for every kilogram of water, 0.820 moles of dissociated ions from NaCl are dissolved.

8 0

3 years ago

The __________ is the part of the solution that is in the greater quantity, and the __________ is the smaller portion of the sol

nikklg [1K]

Answer:

its c

Explanation:

solvent is the part of the solution that is in the greater quantity, and solute is the smaller portion of the solution

hope this helps :)

7 0

3 years ago

Read 2 more answers

Carbon dioxide (CO2) fills a closed, rigid tank fitted with a paddle wheel, initially at 80°F, 30 lbf/in2, and a volume of 1.6 f

solong [7]

Answer:

The answer to this question can be given as:

The initial pressure P= 30 lbf/in2

The initial temperature T1=80°F.

The initial volume=final volume V= 1.6 ft3.

Final temperature T2=500°F

Heat transfer Q=-2.6 Btu.

pressure (P) (lbf/in2) change into lbf/ft2

P=30 lbf/in2=4320lbf/ft2.

Temperature (T1) °F change into °K

temperature T1=80°F=539.67 °K

Ideal gas formula:

M=PV/RT1. where T1=initial temperature.

M=4320*1.6/35.114*539.67.

M=0.364749 lb Mass at Carbon dioxide (CO2).

DQ=DU+W second law.

-2.6=MCV(T2-T1)+ W

-2.6-(0.364749*1.6(500-80))=W

W=-27.111 b+u am----> work done.

Explanation:

The explanation to this question can be given as:

Firstly we write the equation that is given in the question like, pressure, volume, gas constant, temperature. Then we covert the pressure and temperature into there possible values. Then We apply the formula of Ideal gas that is M=PV/RT1. where M is the mass, P is the pressure , V is the volume , R is the gas constant (0.08206 L·atm·K−1·mol−1) and T1 is the initial temperature. Then we use the second formula that is DQ=DU+W. Where DQ= Heat transfer, DU=MCV(T2-T1)and W= work. It is used for finding work.

8 0

3 years ago

When 2.00 g of methane are burned in a bomb calorimeter, the change in temperature is 3.08°C. The heat capacity of the calorimet

melisa1 [442]

Answer:

The approximate molar enthalpy of combustion of this substance is -66 kJ/mole.

Explanation:

First we have to calculate the heat gained by the calorimeter.

$q=c\times \Delta T$