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3 years ago

Short note on dung fertilization

Chemistry

2 answers:

bogdanovich [222]3 years ago

7 0

Answer:

Most manure consists of animal feces; other sources include compost and green manure. Manures contribute to the fertility of soil by adding organic matter and nutrients, such as nitrogen, that are utilised by bacteria, fungi and other organisms in the soil.

Explanation:

Hope it is helpful....

mestny [16]3 years ago

6 0

Answer:

Animal manure, such as chicken manure and cow dung, has been used for centuries as a fertilizer for farming. It can improve the soil structure (aggregation) so that the soil holds more nutrients and water, and therefore becomes more fertile. ... Manure is also commercially composted and bagged and sold as a soil amendment.

Explanation:

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I kind of get how to do this but don’t fully #’s 2, 3, and 4

raketka [301]

Answer:2. 109 g NaCl

3. 31.9 g ZnCl2

4. 15.4 g Al2O3

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Convert moles to mass.

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3 years ago

Ethanol (c2h5oh) burns according to the equation c2h5oh(l) + 3o2(g) â 2co2(g) + 3h2o(l), Î´h= -1367 kj/mol. how much heat is rel

Eva8 [605]

Molar mass of ethanol is: 46 grams/moles
C2H6O-> 2x12 + 6x1+ 16x1 (see periodic table)

If 46 g correspond to 1 mol, how much moles correspond 35 g?
46g ====1mol
35g====x
x= 35/46
x=0,76 mol

-1367 kj/mol, means that there are -1367 kj in one mol
1mol ==== -1367 kj
0,76mol==== x
x=- 1040Kj

Ethanol released 1040 Kj.

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3 years ago

If a body of water has high turbidity levels, what can most likely be concluded?

harina [27]

Unsafe to dono because it’s way too high

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3 years ago

How would one convert 36 yd to centimeters (2.54 cm = 1 in)

ValentinkaMS [17]

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3 0

3 years ago

Read 2 more answers

The heat of combustion (∆H) for an unknown hydrocarbon is -8.21 kJ/mol. If 0.424 mol of the hydrocarbon is burned in a bomb calo

klio [65]

When 0.424 moles of an unknown hydrocarbon (∆Hc = -8.21 kJ/mol) is burned in a bomb calorimeter (C = 1.12 kJ/°C), the change in the temperature is 3.10 °C.

The heat of combustion (∆Hc) for an unknown hydrocarbon is -8.21 kJ/mol. The heat released by the combustion of 0.424 moles of the hydrocarbon is:

$Qc = 0.424 mol \times \frac{(-8.21kJ)}{mol} = -3.48 kJ$

According to the law of conservation of energy, the sum of the heat released by the combustion (Qc) and the heat absorbed by the bomb calorimeter (Qb) is zero.

$Qc + Qb = 0\\\\Qb = -Qc = 3.48 kJ$

Given the heat absorbed by the bomb calorimeter (Qb) and the heat capacity of the bomb calorimeter (C), we can calculate the temperature change (ΔT) using the following expression.

$Qb = C \times \Delta T\\\\\Delta T = \frac{Qb}{C} = \frac{3.48 kJ}{1.12 kJ/\° C } = 3.10 \° C$

When 0.424 moles of an unknown hydrocarbon (∆Hc = -8.21 kJ/mol) is burned in a bomb calorimeter (C = 1.12 kJ/°C), the change in the temperature is 3.10 °C.

Learn more: brainly.com/question/24245395

8 0

3 years ago

Short note on dung fertilization ​

Short note on dung fertilization