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malfutka [58]
3 years ago
15

A tow truck does 10,000 J of work in 5 seconds. Calculate the power.

Chemistry
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

power is work/time so 10,000j/5s=2000J/s

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The rate constant for the decomposition of nitrogen dioxide NO2(g) LaTeX: \longrightarrow⟶ NO (g) + 1/2 O2(g) with a laser beam
aleksley [76]

Answer :

The time taken by the reaction is 19.2 seconds.

The order of reaction is, second order reaction.

Explanation :

The general formula to determine the unit of rate constant is:

(Concentration)^{(1-n)}(Time)^{-1}

Unit of rate constant                           Order of reaction

Concentration/Time                                        0

Time^{-1}                                                              1

(Concentration)^{-1}Time^{-1}                                 2

As the unit of rate constant is M^{-1}min^{-1}. So, the order of reaction is second order.

The expression used for second order kinetics is:

kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}

where,

k = rate constant = 1.95M^{-1}s^{-1}

t = time = ?

[A_t] = final concentration = 0.97 M

[A_o] = initial concentration = 2.48 M

Now put all the given values in the above expression, we get:

1.95\times t=\frac{1}{0.97}-\frac{1}{2.48}

t=0.32min=0.32\times 60s=19.2s

Therefore, the time taken by the reaction is 19.2 seconds.

8 0
3 years ago
How does one recognize a redox reaction?
nika2105 [10]

Answer:

A.

Explanation:

A redox reaction is a reaction when oxidation states (or numbers) change during reaction.

3 0
3 years ago
If a gas occupies 1532.7 mL at standard temperature, what volume does it occupy at 49.4 ºC if the pressure remains constant?
ElenaW [278]

Answer:

a. 1810mL

Explanation:

When conditions for a gas change under constant pressure (and the number of molecules doesn't change), it follows Charles' Law:

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}  where the temperatures must be measured in Kelvin

To convert from Celsius to Kelvin, add 273, or use the equation:  T_C+273=T_K

For this problem, one must also recall that standard temperature is 0°C (or 273K).

So, T_1 = 273[K], and T_2 = (49.4+273)[K]=322.4[K].

\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\dfrac{(1532.7[mL])}{(273[K])}=\dfrac{V_2}{(322.4[K])}

\dfrac{(1532.7[mL])}{(273[K\!\!\!\!\!{-}])}(322.4[K\!\!\!\!\!{-}] )=\dfrac{V_2}{(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})}(322.4[K]\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{----})

1810.04571428[mL]=V_2

Adjusting for significant figures, this gives V_2=1810[mL]

4 0
2 years ago
How many grams Kl are needed to prepare 100.mL of 0.55M solution?​
Makovka662 [10]

Answer:

Explanation:

100mL = 0.1L

0.55 M = mol/0.1 L

mol = 0.055 mol

molar mass of KI = 165.998 g

0.055 * 165.998 = 9.13 g of KI

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2 years ago
How is the nucleus of an atom split?
AnnZ [28]
Collision with a high-speed particle
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