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lesantik [10]
3 years ago
12

Why would the pressure of a sample of gas at a constant volume fall .10 atm?

Chemistry
1 answer:
Lisa [10]3 years ago
7 0

Answer:

As the temperature of a sample of gas falls from 45.0ºC to 30.0ºC, its pressure falls to 300.

Explanation:

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What is the volume of 40g of sugar given it’s listed density
lora16 [44]

Answer:

25.157 cm³

Explanation:

Data Given:

Mass of Sugar (m) = 40g

Density of sugar given in literature = 1.59 g/cm³

Volume of Sugar = ?

The formula will be used is

                              d = m/v ........................................... (1)

where

D is density

m is the mass

v is the volume

So

Rearrange the Equation (1)

                              d x v = m

                               v = m/ d         ................................................ (2)

put the given values in Equation  (2)

                       v = 40g / 1.59 g/cm³

                       v = 25.157 cm³

volume of 40 g of sugar = 25.157 cm³

8 0
3 years ago
Draw a physical model that shows the reaction of zinc metal and hydrochloric acid (hydrogen chloride).
Brilliant_brown [7]

Answer:

Zinc + Hydrochloric Acid Zinc Chloride and Hydrogen Gas

Zn + 2HCI - ZnCl2 + H2

Explanation:

Be sure to label your model to clearly show how you are representing the atoms

3 0
2 years ago
Chloroform (CHCl3), an important solvent, is produced by a reaction between methane and chlorine. CH4(g) + 3 Cl2(g) CHCl3(g) + 3
PIT_PIT [208]
CH₄(g) + 3 Cl₂(g) → CHCl₃(g) + 3 HCl(g)
From the equation we notice that 1 mole of methane produces 1 mole of chloroform:
16 g Methane → 119.38 g Chloroform
?   g Methane → 37.5 g Chloroform
by cross multiplication:
= (16 * 37.5) / 119.38 = 5.0 g methane
4 0
3 years ago
PLEASE HELP<br><br> is this a chemical or physical change???
skad [1K]

Answer:

Chemical, cause physical are changes affecting the form of a chemical substance, but not its chemical composition. This doesn't affect the substance but the composition.

Explanation:

5 0
3 years ago
Read 2 more answers
An acid with the general formula RCOOH is used to make a 0.10 M solution in water. The pH of this acid solution is measured as 3
Sati [7]

Answer:

0.159 \%

Explanation:

The acid will dissociate according to the reaction shown below:-

RCOOH + H_2O\rightleftharpoons RCOO^- + H_3O^+

Given that, pH=3.8

The concentration of can be determined from the expression fo pH as:-

pH = - log [H^+]

3.8  = - log [H^+]

[H^+] = 1.59\times 10^{-4}\ M

The initial concentration of RCOOH was 0.10 M, then the percent dissociation was- calculated as shown below:-

\% \ dissociation=\frac{1.59\times 10^{-4}}{0.10}\times 100=0.159\ \%

3 0
2 years ago
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