Answer:
25.157 cm³
Explanation:
Data Given:
Mass of Sugar (m) = 40g
Density of sugar given in literature = 1.59 g/cm³
Volume of Sugar = ?
The formula will be used is
d = m/v ........................................... (1)
where
D is density
m is the mass
v is the volume
So
Rearrange the Equation (1)
d x v = m
v = m/ d ................................................ (2)
put the given values in Equation (2)
v = 40g / 1.59 g/cm³
v = 25.157 cm³
volume of 40 g of sugar = 25.157 cm³
Answer:
Zinc + Hydrochloric Acid Zinc Chloride and Hydrogen Gas
Zn + 2HCI - ZnCl2 + H2
Explanation:
Be sure to label your model to clearly show how you are representing the atoms
CH₄(g) + 3 Cl₂(g) → CHCl₃(g) + 3 HCl(g)
From the equation we notice that 1 mole of methane produces 1 mole of chloroform:
16 g Methane → 119.38 g Chloroform
? g Methane → 37.5 g Chloroform
by cross multiplication:
= (16 * 37.5) / 119.38 = 5.0 g methane
Answer:
Chemical, cause physical are changes affecting the form of a chemical substance, but not its chemical composition. This doesn't affect the substance but the composition.
Explanation:
Answer:
0.159 \%
Explanation:
The acid will dissociate according to the reaction shown below:-

Given that, pH=3.8
The concentration of can be determined from the expression fo pH as:-
pH = - log ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
3.8 = - log ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
= 
The initial concentration of RCOOH was 0.10 M, then the percent dissociation was- calculated as shown below:-
