All categories

3 years ago

describe how astronomers are able to use the light from a distant star to determine what elements make up the stars.

Chemistry

1 answer:

dlinn [17]3 years ago

7 0

Answer:

The spectra of the Sun and stars exhibited bright and dark lines called Fraunhofer lines. These were shown to be caused by elements emitting or absorbing light at specific wavelengths. Because each element emits or absorbs light only at specific wavelengths, the chemical composition of stars can be determined.

You might be interested in

The chemists is another name for the periodic table

Slav-nsk [51]

Answer:No

Explanation:

the answer is no,because in the picture below it is saying Dmitri Mendeleev is the chemist not the periodic table.

8 0

3 years ago

Benzoic acid has Ka =6.5× 10 ?5 , and citric acid has Ka =7.2× 10 ?4. What is the stronger conjugate base?

likoan [24]

Answer: The stronger conjugate base is, Citric acid.

Explanation :

The value of dissociation constant of Benzoic acid is higher than the citric acid. This means that the acid will readily dissociate and stronger will be the acid. Higher the value of dissociation constant of an acid weaker will be its conjugate base and the lower value of dissociation constant of an acid means that the stronger will be its conjugate base.

Therefore, the stronger conjugate base is Citric acid.

4 0

3 years ago

Element "Z" has 2 naturally occurring isotopes with the following masses and natural abundances:

fiasKO [112]

Answer: the atomic Mass of Z is 46.26

Explanation:Please see attachment for explanation

3 0

3 years ago

Need help matching them with correct formula

Anarel [89]

Answer:

Here you go I hope it helped you! :) good luck!

4 0

3 years ago

. Metallic iron has a body-centered cubic lattice with all atoms at lattice points and a unit cell whose edge length is 286.6 pm

adell [148]

Answer:

$\large \boxed{\text{55.8 u}}$

Explanation:

1. Calculate the volume of the unit cell

V = l³ = (2.866 × 10⁻⁸ cm)³ = 2.354 × 10⁻²³ cm³

2. Calculate the mass of a unit cell

$\text{Mass} = 2.866 \times 10^{-23}\text{ cm}^{3} \times \dfrac{\text{7.87 g}}{\text{1 cm}^{3}} = 1.853 \times 10^{-22} \text{ g}$

3. Calculate the mass of one atom

A body-centred unit cell contains two atoms.

$\text{Mass of 1 atom} = \dfrac{1.853 \times 10^{-22} \text{ g}}{\text{2 atoms}} \times \dfrac{\text{1 u}}{1.661 \times 10^{-24}\text{ g}} = \textbf{55.8 u}\\\\\text{The molar mass of Fe from the Periodic Table is $\large \boxed{\textbf{55.845 g/mol}}$}$

6 0

3 years ago