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Digiron [165]
3 years ago
10

What can be seen with unaided eyes or with a microscope.

Chemistry
1 answer:
Elena-2011 [213]3 years ago
4 0

Answer:

microorganism can bee seen yes

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Which of the following best represents the general form of a chemical equation?
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The general form would be
Reactants ---> Products
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Which does not affect global wind belts
vekshin1

Answer:

b

Explanation:

its local

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Which of the following is the ground state of an atom? Which is its excited state? Which is an impossible electron configuration
Rus_ich [418]

For this specific problem, these would be the answer to the following choices:

a. excited

b. ground

c. impossible

I am hoping that these answers have satisfied your queries and it will be able to help you, thank you and have a nice day.

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Acid-catalyzed dehydration of secondary and tertiary alcohols proceeds through an E1 mechanism. The first step is the protonatio
Over [174]

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Most substituted alkene is produced as a major product

Explanation:

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4 0
3 years ago
A gas occupies 100 mL at 150. kPa. Find its volume at 200. kPa. You must show all your work to receive credit. Be sure to identi
PtichkaEL [24]

The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:

PV = k

where k is a constant.

We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,

P₁V₁ = P₂V₂

Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.

In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa.  Substituting these values in the previous equation and clearing V₂, we have,

P₁V₁ = P₂V₂ → V₂ = \frac{P1V1}{P2}  

→ V₂ = \frac{100 mL x 150 kPa}{200 kPa}

→ V₂ = 75 mL

Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL

6 0
3 years ago
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