Answer:
Please see the answer..hope its works
Explanation:
The NMR spectrometer will acquire data for the wrong chemical shift range and you will potentially have skewed data when opening spinworks-NMR spectrometer examines a specific 12 ppm range based on the expected solvent peak, and if a different solvent is used a different range may be examined
To explain further, If the user declares the wrong solvent, one of two things may happen. Firstly, the spectrometer may not be able to establish a deuterium lock and will report an error and not run the sample. Secondly, the spectrometer may be able to establish a lock despite the fact that the deuterium signal is off resonance. If the lock is established, the field strength will be set to a value appropriate to put the declared solvent signal on-resonance. When a proton NMR spectrum is collected, the chemical shift scale will be incorrect by an amount equal to the proton chemical shift difference between the true solvent and the declared solvent.
Answer:
C8H17N
Explanation:
Mass of the unknown compound = 5.024 mg
Mass of CO2 = 13.90 mg
Mass of H2O = 6.048 mg
Next, we shall determine the mass of carbon, hydrogen and nitrogen present in the compound. This is illustrated below:
For carbon, C:
Molar mass of CO2 = 12 + (2x16) = 44g/mol
Mass of C = 12/44 x 13.90 = 3.791 mg
For hydrogen, H:
Molar mass of H2O = (2x1) + 16 = 18g/mol
Mass of H = 2/18 x 6.048 = 0.672 mg
For nitrogen, N:
Mass N = mass of unknown – (mass of C + mass of H)
Mass of N = 5.024 – (3.791 + 0.672)
Mass of N = 0.561 mg
Now, we can obtain the empirical formula for the compound as follow:
C = 3.791 mg
H = 0.672 mg
N = 0.561 mg
Divide each by their molar mass
C = 3.791 / 12 = 0.316
H = 0.672 / 1 = 0.672
N = 0.561 / 14 = 0.040
Divide by the smallest
C = 0.316 / 0.04 = 8
H = 0.672 / 0.04 = 17
N = 0.040 / 0.04 = 1
Therefore, the empirical formula for the compound is C8H17N
The answer to this question would be the rate of change
Answer:
The wavelength the student should use is 700 nm.
Explanation:
Attached below you can find the diagram I found for this question elsewhere.
Because the idea is to minimize the interference of the Co⁺²(aq) species, we should <u>choose a wavelength in which its absorbance is minimum</u>.
At 400 nm Co⁺²(aq) shows no absorbance, however neither does Cu⁺²(aq). While at 700 nm Co⁺²(aq) shows no absorbance and Cu⁺²(aq) does.
