All categories

3 years ago

Prove law of conservation of momentum ,??

Physics

1 answer:

ziro4ka [17]3 years ago

7 0

Explanation:

$\law \: of \: conservation \: of \: momentum)$

$\frac{initial}{m1u1 + m2u2} = \frac{fi}{m 2u2}$

<h3>BEFORE COLLISION)  INITIAL MOM. OF BODY A </h3>

PiA = m1u1

After collision) .................. B I. e piB = m2u2

<h2>FINÅL MOMENTUM OF BØDY A I. e PfA= m1v1</h2>

FINAL .......... B I. e PfB = m2v2

ùr ãñswer ✌️

♠️♠️♠️♠️♠️♠️

You might be interested in

Find the ratio of the gravitational force between two planets if the masses of both planets are quadrupled but the distance betw

Snezhnost [94]

Answer:

The ratio of the new force over the original force is 16

Explanation:

Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:

$F_G=G\,\frac{M_1\,\,M_2}{D^2}$

So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:

$F'_G=G\,\frac{4M_1\,\,4M_2}{D^2}=G\,\frac{16\,\,M_1\,\,M_2}{D^2}=16\,\,G\,\frac{M_1\,\,M_2}{D^2}= 16\,\,F_G$

which is 16 times the original force.

So the ratio of the new force over the original force is 16

5 0

3 years ago

In the future, an experimental spacecraft leaves space dock for a test flight. After flying in a very large circle at constant s

Fantom [35]

Answer:

2.58 x 10⁸ m/s

Explanation:

Time dilation fomula will be applicable here, which is given below.

t = \frac{T}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}

Where T is dilated time or time observed by clock in motion , t is stationary time , v is velocity of clock in motion and c is velocity of light .

c is 3 times 10⁸ ms⁻¹ , T is 7.24 h , t is 3.69 h. Put these values in the formula

7.24 = \frac{3.69}{\left ( 1-\frac{v^2}{c^2} \right )^\frac{1}{2}}\\

\frac{v^2}{c^2}=0.744\\\\

v=2.58\times 10^8

5 0

3 years ago

You are a project manager for a manufacturing company. One of the machine parts on the assembly line is a thin, uniform rod that

ra1l [238]

Answer:

a) $I=0.012\ kg.m^2$

b) $I=0.012\ kg.m^2$

Explanation:

Given that:

mass of rod, $m=0.4\ kg$

length of the rod, $l=0.6\ kg$

(a)

Moment of inertia of rod about its center and perpendicular to the rod is given as:

$I=\frac{1}{12} m.l^2$

$I=\frac{1}{12} 0.4\times 0.6^2$

$I=0.012\ kg.m^2$

(b)

Moment of inertia on bending the rod to V-shape of 60 degree angle and axis being perpendicular to the plane of V at the vertex.

We treat it as two rod with axis of rotation at the end and perpendicular to the plane of rotation. 

So, the mass and the length of the rod will become half of initial value.

$I=I_1+I_2$

$I=\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2 +\frac{1}{3} \frac{m}{2} (\frac{l}{2})^2$

$I=2[ \frac{1}{3}\times 0.2\times 0.3^2]$

$I=0.012\ kg.m^2$

7 0

3 years ago

Which statement aboutſatmospheric pressure near Earth's surface is true?

Marizza181 [45]

Answer:

Option B) It decreases as someone moves away from earth's surface.

Explanation:

The atmospheric pressure at the surface of the earth is at maximum, it is seen that as we move away from the surface of the earth the pressure decreases. As on the top of mountains the atmospheric pressure is found to be low as compared to the surface of the earth.

It is assumed that the atmospheric pressure is caused due to hydrostatic measurements where the changes caused by weight of air are measured.

Also, it is observed that when there is an elevation, the atmospheric pressure decreases.

6 0

3 years ago

5. You head downstream on a river in an outboard.

Bezzdna [24]

Answer:

hope this helps you're welcome

6 0

3 years ago

Prove law of conservation of momentum ,??​

Prove law of conservation of momentum ,??