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2 years ago

Prove law of conservation of momentum ,??

Physics

1 answer:

ziro4ka [17]2 years ago

7 0

Explanation:

$\law \: of \: conservation \: of \: momentum)$

$\frac{initial}{m1u1 + m2u2} = \frac{fi}{m 2u2}$

<h3>BEFORE COLLISION)  INITIAL MOM. OF BODY A </h3>

PiA = m1u1

After collision) .................. B I. e piB = m2u2

<h2>FINÅL MOMENTUM OF BØDY A I. e PfA= m1v1</h2>

FINAL .......... B I. e PfB = m2v2

ùr ãñswer ✌️

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A girl weighing 50 kgf wears sandals of pencil heel of area of cross section 1 cm^2, stands on the floor.An elephant weighing 20

Klio2033 [76]

Answer:

$\boxed{{\boxed{\blue{ 12.5}}}}$

Explanation:

Given, for girl : Weight or force;

$\rm \: F_1 = 50 \: kgf$

Area of both heels;

$\rm \: A_1 = \; 2 ×1 \; cm^2 = 2 \: cm^2$

$\rm \: Pressure \: P_1 = \cfrac{F_1}{ A_1 } = \dfrac{50 \: kgf}{2 \: cm {}^{2} } = 25 \: kgf \: cm {}^{ - 1}$

For elephant, Weight = Force $\rm F_2$ = 2000 kg•f

Area of 4 feet;

$\rm \: A_2 = \; 4 \times 250 \; cm^2 = 1000 \: cm^2$

$\rm \: Pressure \: P_2 = {F_2}/{A_2} \; = \cfrac{2 \cancel{0 00 }\: kgf}{1 \cancel{000} \: cm^2} = 2 \: kgf \: { \:cm}^{- 1}$

Now;

$\rm = \dfrac{Pressure \: Exerted \: by \: the \: Girl}{Pressure \: exerted \: by \: the \: elephant}$

$= \rm \: P_1/P_2$

$\implies \rm\cfrac{25 \: kgf \: \: cm {}^{ - 2} }{2 \: kgf \: cm {}^{ - 2} } = \rm\cfrac{25 \: \cancel{kgf \: \: cm {}^{ - 2}} }{2 \: \cancel{ kgf \: cm {}^{ - 2}} } = \boxed{12.5}$

Thus, the girl's pointed heel sandals exert 12.5 times more pressure P than the pressure P exerted by the elephant.

I aspire this helps!

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ipn [44]

Explanation:

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2 years ago

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irina [24]

Answer:

$t=\frac{x_f-x_i}{v}$

Explanation:

Starting from the equation:

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First of all, let's multiply by t on both sides:

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And then, let's divide by v on both sides:

$\frac{vt}{v}=\frac{x_f-x_i}{v}\\t=\frac{x_f-x_i}{v}$

So, finally

$t=\frac{x_f-x_i}{v}$

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2 years ago

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11Alexandr11 [23.1K]

Answer:

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Explanation:

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Prove law of conservation of momentum ,??​

Prove law of conservation of momentum ,??