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3 years ago

Prove law of conservation of momentum ,??

Physics

1 answer:

ziro4ka [17]3 years ago

7 0

Explanation:

$\law \: of \: conservation \: of \: momentum)$

$\frac{initial}{m1u1 + m2u2} = \frac{fi}{m 2u2}$

<h3>BEFORE COLLISION)  INITIAL MOM. OF BODY A </h3>

PiA = m1u1

After collision) .................. B I. e piB = m2u2

<h2>FINÅL MOMENTUM OF BØDY A I. e PfA= m1v1</h2>

FINAL .......... B I. e PfB = m2v2

ùr ãñswer ✌️

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A 1.50 3 103 - kg car starts from rest and accelerates uniformly to 18.0 m/s in 12.0 s. Assume that air resistance remains const

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Answer:

Explanation:

let force exerted by engine be F.Net force =( F-400)N, applying newton law

F-400 = 1.5 x 10³x18 =27000 ,

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3 years ago

Read 2 more answers

PLEASE HELP

hichkok12 [17]

The correct answer is 195.6 N

Explanation:

Different from the mass (total of matter) the weight is affected by gravity. Due to this, the weight changes according to the location of a body in the universe as gravity is not the same in all planets or celestial bodies. Moreover, this factor is measured in Newtons and it can be calculated using this simple formula W (Weight) = m (mass) x g (force of gravity). Now, leps calculate the weigh of someone whose mass is 120 kg and it is located on the moon:

F = 120 kg x 1.63 m/s2

F= 195.6 N

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3 years ago

What is the electric force acting between two charges of -0.0045 C and -0.0025 C that are 0.0060 m apart? Use Fe=kq1q2/r^2 and k

oksano4ka [1.4K]

Answer:

D. 2.8 × 10⁹ N

Explanation:

The force between two charges is directly proportional to the amount of charges at the two points and inversely proportional to the square of distance between the two points.

Fe= k Q₁Q₂/r²

Q₁= -0.0045 C

Q₂= -0.0025 C

r= 0.0060 m

k= 9.00 × 10 ⁹ Nm²/C²

Fe= (9.00 × 10 ⁹ Nm²/C²×-0.0045 C×-0.0025 C)/0.0060²

=2.8 × 10⁹ N

4 0

3 years ago

Read 2 more answers

Prove law of conservation of momentum ,??​

Prove law of conservation of momentum ,??