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AveGali [126]
3 years ago
7

Two gases are placed in a sealed flask and allowed to react. Which statement is true about the concentrations of the reactants a

nd products when this closed system reaches dynamic equilibrium? They will be equal and constant. They will be equal but continuously changing. They will not necessarily be equal, and they will be continuously changing. They will not necessarily be equal, but they will be constant.
Chemistry
2 answers:
3241004551 [841]3 years ago
7 0
The correct answer is they will not necessarily be equal, but they will be constant. The change between reactants and products will be going continuously but the concentration is constant.
8090 [49]3 years ago
3 0

D. They will not necessarily be equal, but they will be constant.

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Find the boiling point?<br> 100. g of C2H6O2 dissolved in 200 g of H2O?
aleksklad [387]

Answer:

The correct answer is 104.13ºC

Explanation:

When a solute is added to a solvent, the boiling point of the solvent (Tb) increases. That is a colligative property. The increment in Tb (ΔTb)  is given by the following expression:

ΔTb = Tb - Tbº= Kb x m

Where Tb and Tbº are the boiling points of the solvent in solution and pure, respectively; Kb is a constant and m is the molality of the solution.

In this problem, the solvent is water (H₂O). It is well known that water has a boiling point of 100ºC (Tb). The value of Kb for water is 0.512ºC/m. So, we have to calculate the molality of the solution (m):

m = moles of solute/Kg solvent

The solute is C₂H₆O₂ and we have to calculate the number of moles of this component by dividing the mass into the molecular weight (Mw):

Mw(C₂H₆O₂)= (2 x 12 g/mol) + (6 x 1 g/mol) + (2 x 16 g/mol)= 62 g/mol

⇒ moles of C₂H₆O₂ = mass/Mw = 100 g/(62 g/mol) = 1.613 moles

Now, we need the mass of solvent (H₂O) in kilograms, so we divide the grams into 1000:

200 g x 1 kg/1000 g = 0.2 kg

Finally, we calculate the molality as follows:

m = 1.613 moles of C₂H₆O₂/0.2 kg = 8.06 moles/kg = 8.06 m

The increment in the boiling point will be:

ΔTb = Kb x m = 0.512ºC/m x 8.06 m = 4.13ºC

So, the boiling point of pure water (Tbº=100ºC) will increase in 4.13ºC:

Tb= 100ºC+4.12ºC= 104.13ºC

5 0
3 years ago
Investigate why some element’s symbols derived from their old names.
Gekata [30.6K]

Answer:

you know just in order to bring that nostalgia into chemists minds

Explanation:

3 0
3 years ago
Can u answer this?<br> Mass: 126 g<br> Volume: 15 cm to the third power<br> Density:?
Andre45 [30]

Answer:

Calculate density

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126

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Density

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Explanation:

4 0
3 years ago
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Leona [35]

Answer:

2.0 Liters

Explanation:

Boyles law

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7 0
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Now if 4 quarts is equal to 1 gallon.

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8 0
3 years ago
Read 2 more answers
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