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Bingel [31]
3 years ago
15

PLEASE HELP!!!

Chemistry
2 answers:
katen-ka-za [31]3 years ago
8 0
The answer is D. Appearance
Anarel [89]3 years ago
3 0

Answer:

E

Explanation:

You can't really tell by their masses. It's very possible to amount them to the same mass because FeS is actually the same when you mix iron and sulfur, therefore producing the same mass.

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Trimix 10/50 is a gas mixture that contians 10% oxygen and 50% helium, and the rest is nitrogen. If a tank of trimix 10/50 has a
Marat540 [252]

Answer : The partial pressure of helium is, 1.815\times 10^4KPa

Solution : Given,

Molar mass of O_2 = 32 g/mole

Molar mass of helium = 4 g/mole

Molar mass of N_2 = 28 g/mole

Total pressure of gas = 2.07\times 10^4KPa

As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.

First we have to calculate the moles of oxygen, helium and nitrogen gas.

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{10g}{32g/mole}=0.3125moles

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{50g}{4g/mole}=12.5moles

\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{40g}{28g/mole}=1.428moles

Now we have to calculate the total number of moles of gas mixture.

\text{Total number of moles of gas}=\text{Moles of oxygen gas}+\text{Mole of helium gas}+\text{Moles of nitrogen gas}

\text{Total number of moles of gas}=0.3125+12.5+1.428=14.24moles

Now we have to calculate the moles fraction of helium gas.

\text{Mole fraction of He gas}=\frac{\text{Moles of He gas}}{\text{Total number of moles of gas}}=\frac{12.5}{14.25}=0.877

Now we have to calculate the partial pressure of helium.

p_{He}=X_{He}\times P_T

where,

p_{He} = partial pressure of helium

P_T = total pressure

X_{He} = mole fraction of helium

Now put all the given values in this formula, we get

p_{He}=(0.877)\times (2.07\times 10^4KPa)=1.815\times 10^4KPa

Therefore, the partial pressure of helium is, 1.815\times 10^4KPa

8 0
3 years ago
Calculate OH- given H3 O+ = 1.40 *10^-4 M
vova2212 [387]

3.16 X 10^-11 M is the [OH-] concentration when H3O+ = 1.40 *10^-4 M.

Explanation:

data given:

H30+= 1.40 X 10^-4 M\

Henderson Hasslebalch equation to calculate pH=

pH = -log10(H30+)

putting the values in the equation:

pH = -log 10(1.40 X 10^-4 M)

pH = 3.85

pH + pOH =14

pOH = 14 - 3.85

pOH = 10.15

The OH- concentration from the pOH by the equation:

pOH = -log10[OH-]

10.5= -log10[OH-]

[OH-] = 10^-10.5

[OH-]  = 3.16 X 10^-11 is the concentration of OH ions when hydronium ion concentration is 1.40 *10^-4 M.

8 0
3 years ago
2C6H10 + 17O2 = 12CO2 + 10H2O
Ad libitum [116K]

Answer:

n O2 = 2.125 mol

Explanation:

balanced reaction:

  • 2C6H10 + 17O2 → 12CO2 + 10H2O

∴ n CO2 = 1.5 mol

⇒ n O2 = (1.5 mol CO2)*(17 mol O2/12 mol CO2)

⇒ n O2 = 2.125 mol

6 0
3 years ago
Do hot things, like water or magma, always rise?
Olegator [25]

Answer:

Explanation:

No not always but it is more likely they will

8 0
3 years ago
There are five constitutional isomers with the molecular formula C6H14. When treated with chlorine at 300°C, isomer A gives a mi
ozzi

Answer:

Pentane or 2,2-dimethylbutane  

Explanation:

I've numbered the isomeric hexanes from 1 to 5 and labelled the sets of equivalent hydrogens.

The results are

Isomer 1— three sets of equivalent hydrogens

Isomer 2— five sets of equivalent hydrogens

Isomer 3— four sets of equivalent hydrogens

Isomer 4— two sets of equivalent hydrogens

Isomer 5— three sets of equivalent hydrogens

Each set will give one monochloro substitution product.

4 = A. Two monochloro isomers.

2 = B. Five monochloro isomers.

3 = C. Four monochloro isomers.

Isomers 1 and 5 each give three monochloro isomers.

Thus, we cannot assign Structure D definitively.

D is either pentane or 2,2-dimethylbutane.

5 0
3 years ago
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