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kiruha [24]
3 years ago
13

How many moles of glucose (C6H12O6) are in 5.0 liters of a 2.5 M C6H12O6 solution?

Chemistry
1 answer:
zhannawk [14.2K]3 years ago
5 0
N = M x V      

n = 2.5 x 5.0
 
n = 12.5 moles of C6H12O6
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How many moles of methanol must be added to 4.50 kg of water to lower its freezing point to -11.0 ∘c? for each mole of solute, t
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<u>Given:</u>

Mass of solvent water = 4.50 kg

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<u>To determine:</u>

Moles of methanol to be added

<u>Explanation:</u>

The freezing point depression ΔTf is related to the molality m through the constant kf, as follows:

ΔTf = kf*m

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m = molality = moles of methanol/kg of water = moles of methanol/4.50 kg

11.0 = 1.86 * moles of methanol/4.50

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