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2 years ago

What is the molar mass of al (clo2)3

Chemistry

1 answer:

frozen [14]2 years ago

4 0

The molar mass is 229.33

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The product side of a chemical reaction is shown.

Inga [223]

The number that represents the coefficient on the product side of the chemical reaction, $-- > 7Ti_2(SO_4)_3$ is 7.

<h3>Coefficients of chemical equations</h3>

In equations representing chemical reactions, the coefficient of each reactant or product of a reaction is the number that comes on the left-hand side just before the chemical formula.

The coefficient of each species in a chemical reaction is obtainable when the equation of the reaction is balanced.

For example, in the following equation: 2A + B = 3C + D

The coefficients of A, B, C, and D are 2, 1, 3, and 1 respectively.

Applying this to the product side of a chemical reaction; $-- > 7Ti_2(SO_4)_3$

It means that the coefficient of the product is 7.

More on coefficients of chemical equations can be found here: brainly.com/question/28294176

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7 0

1 year ago

If a precipitation reaction occurs, what will be the products of the unbalanced

levacccp [35]

Answer:

${ \sf{B. \: AgCl _{(s)} + NaNO _{3(aq)}}}$

Explanation:

Silver chloride precipitates out because it has a low value of Ksp.

7 0

3 years ago

you know the mass of an object and the force applied to the bject to make it move . Which of Newtons laws of motion will help yo

MAVERICK [17]

Answer:

second law of acceleration

Explanation:

hope this helps :)

8 0

2 years ago

Read 2 more answers

If 3.31 moles of argon gas occupies a volume of 100 L what volume does 13.15 moles of argon occupy under the same temperature an

kumpel [21]

Answer:

397 L

Explanation:

Recall the ideal gas law:

$\displaystyle PV = nRT$

If temperature and pressure stays constant, we can rearrange all constant variables onto one side of the equation:

$\displaystyle \frac{P}{RT} = \frac{n}{V}$

The left-hand side is simply some constant. Hence, we can write that:

$\displaystyle \frac{n_1}{V_1} = \frac{n_2}{V_2}$

Substitute in known values:

$\displaystyle \frac{(3.31 \text{ mol})}{(100 \text{ L})} = \frac{(13.15\text{ mol })}{V_2}$

Solving for <em>V</em>₂ yields:

$\displaystyle V_2 = \frac{(100 \text{ L})(13.15)}{3.31} = 397 \text{ L}$

In conclusion, 13.15 moles of argon will occupy 397* L under the same temperature and pressure.

(Assuming 100 L has three significant figures.)

3 0

1 year ago

An ionic compound contains

hodyreva [135]

Answer:

an ionic compound contains ions

Explanation:

7 0

3 years ago