Consider the following 8 numbers, where one labelled x is unknown.
2 answers:
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The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)
Step-by-step explanation:
In a triangle the segment which joining the mid points of two sides:
- Parallel to the 3rd side
- Its length is equal half the length of the 3rd side
- It's called the mid-segment of the triangle
In Δ XYZ
∵ Vertex X is (0 , 7)
∵ Vertex Y is (2 , 5)
∵ Vertex Z is (0 , 1)
∵ The mid-segment of Δ XYZ is parallel to XZ
- The mid-segment intersects the other two sides of the Δ
at their mid-points
∴ The mid-segment intersects XY and YZ at their midpoints
∴ The endpoints of the mid-segment are the midpoints of
XY and YZ
The mid point of a segments whose endpoints are and
is
∵ X = (0 , 7) and Y = (2 , 5)
∴ = 0 and
= 2
∴ = 7 and
= 5
∵ The mid point of XY =
∴ The mid point of XY =
∴ The mid point of XY = (1 , 6)
∵ Z = (0 , 1) and Y = (2 , 5)
∴ = 0 and
= 2
∴ = 1 and
= 5
∵ The mid point of ZY =
∴ The mid point of ZY =
∴ The mid point of ZY = (1 , 3)
∵ The endpoints of the mid-segment are the midpoints of
XY and YZ
∴ The end points of the mid segments are (1 , 6) and (1 , 3)
The coordinates of the endpoints of the mid-segment of Δ XYZ that parallel to XZ are (1 , 6) and (1 , 3)
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The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>Let x be the speed of the walkway.
(2.8 + x) = speed of child moving in direction of the walkway
(2.8 - x) = speed of child moving against the direction of the walkway
Travel time = distance/speed
Travel time of child moving in direction of walkway = 23/(2.8+x)
Total elapsed time given = 29s
23/(2.8 + x)+ 23 / (2.8-x) = 29
LCD = (2.8 + x)(2.8 - x)
simplifying the equation, we get
Speed of walkway = 1.84 m/s
The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.
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