First the theoretical yield of Nabr
by use of mole ratio between FeBr3 and NaBr which is 2:6 the theoretical yield
=2.36 x6/2= 7.08 moles
the % yield = actual yield/ theoretical yield x 100
that is 6.14/7.08 x100= 86.72%
Answer:
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Explanation:
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By looking at the stochiometry, we can conclude that the ratio is 1 :1
2 moles of H2 react to form 2 moles of H2O
hope this helps