Answer:
I say both I hope this helps
Answer:

Explanation:
<u>Given Data:</u>
Mole = n = 3.38 mol
Temp = t = 269 K
Pressure = 1.19 atm
Gas constant = R = 0.08206 L atm K⁻¹ mol⁻¹
<u>Required:</u>
Volume = v = ?
<u>Formula:</u>
Pv = nRT
<u>Solution:</u>
Rearranging formula
![\displaystyle v = \frac{nRT}{P} \\\\v = \frac{(3.38)(0.08206)(269)}{1.19} \\\\v = \frac{74.6}{1.19} \\\\v = 62.7 \ L\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20v%20%3D%20%5Cfrac%7BnRT%7D%7BP%7D%20%5C%5C%5C%5Cv%20%3D%20%5Cfrac%7B%283.38%29%280.08206%29%28269%29%7D%7B1.19%7D%20%5C%5C%5C%5Cv%20%3D%20%5Cfrac%7B74.6%7D%7B1.19%7D%20%5C%5C%5C%5Cv%20%3D%2062.7%20%5C%20L%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)