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Vladimir79 [104]
3 years ago
12

Visible light waves do not diffract as well as radio waves because _____

Physics
1 answer:
VikaD [51]3 years ago
5 0
I think it’s C I’m not completely sure
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Steam enters an adiabatic turbine at 5 MPa and 4500C and leaves at a pressure of 1.4 MPa. Determine the work output of the turbi
REY [17]

Answer:350.92 KJ/kg

Explanation:

Given the process is reversible adiabatic i.e it is isentropic

P_1=5 MPa

T_1=4500 MPa

P_2=1.4 MPa

From steam table

h_1=3317.03KJ/kg

For isentropic process s_1=s_2

at P_2=1.4 MPa

s_2=6.82 KJ/kg-k

h_2=2966.11 KJ/kg

Therefore Work output of the turbine per unit mass of steam is =h_1-h_2

=3317.03-2966.11

=350.92 KJ/kg

8 0
3 years ago
When jumping, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.47 mm .What is the flea's acceleration during the j
garri49 [273]
We can use kinematics here if we assume a constant acceleration (not realistic, but they want a single value answer, so it's implied). We know final velocity, vf, is 1.0 m/s, and we cover a distance, d, of 0.47mm or 0.00047 m (1m = 1000mm for conversion). We also can assume that the flea's initial velocity, vi, is 0 at the beginning of its jump. Using the equation vf^2 = vi^2 + 2ad, we can solve for our acceleration, a. Like so: a = (vf^2 - vi^2)/2d = (1.0^2 - 0^2)/(2*0.00047) = 1,064 m/s^2, not bad for a flea!
8 0
3 years ago
Read 2 more answers
This problem has been solved!
AleksAgata [21]

Answer:the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward.

Explanation:

When a ball is tossed vertically upwards, it reaches its maximum point. This maximum point is known as the maximum height of the ball. At this maximum height, its velocity is zero, its acceleration is directed downwards and the force of gravity acting in the ball is directed downwards towards the earth.

6 0
3 years ago
Ted lifts a 10N weight at a height of 1.5 m in 1
masha68 [24]

Answer:

D. Ted expanded more power.

Explanation:

Given the following data;

For Ted.

Force = 10N

Height = 1.5m

Time = 1 seconds

To find Ted's power;

Power = workdone/time

But workdone = force * distance

Workdone = 10 * 1.5

Workdone = 15 Nm

Power = 15/1

Power = 15 Watts.

For Johnny.

Force = 10N

Height = 1.5m

Time = 2 seconds

To find Ted's power;

Power = workdone/time

But workdone = force * distance

Workdone = 10 * 1.5

Workdone = 15 Nm

Power = 15/2

Power = 7.5 Watts

Therefore, from the calculations we can deduce and conclude that Ted expanded more power.

5 0
3 years ago
Trong thực nghiệm nhiễu xạ qua 1 khe hẹp, bề rộng khe là 2.10-5 m, màn quan sát đặt cách khe 0,5 m. Chiếu ánh sáng có bước sóng
satela [25.4K]

Answer:

tyygggghgtyhyrdfgyyyhjjillbxsrfvgygvnjj

Explanation:

cffczhxucuxoyitxohvojcdivbjv ohxc

5 0
3 years ago
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