What to do if one day your partner wants you but the next day are unsure about you should I try to make it work or leave ..

1 answer:

6 0

Leave them, listen you are better than being with someone who is unsure. If you are 100% in this they need to match the energy. The purpose of dating is going into marriage eventually and imagine if when you get married they are like “wait I don’t know actually”. True me dump them and don’t look back

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What imaginary line marks the southern end of the tropical zone

vitfil [10]

The Tropic of Capricorn is significant to understanding the Earth's geography because it marks the southern boundary of tropics.

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3 years ago

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What motivates you to learn physics?

xz_007 [3.2K]

I guess it's a little different for everyone. Physics ultimately is the study of the universe and every component of it, and physics studies why things are the way they are and characteristics that control the way things act.

For me, I am motivated by my natural curiosity: "why is the sky blue?"... that sorta thing. I want to know the reasons behind phenomena like why the earth spins and how fast a kettle boils if it has X litres of water. Physics, unlike any other discipline, can explain this sort of thing. And for me that's so valuable as in my opinion the way to truly understand the world we live in is to immerse in the physics behind the way things are.

Curiosity and a desire to know why is arguably the best explanation for wanting to learn physics.

As someone in grade 12 doing physics I can tell you that studying physics is extremely rewarding yet extremely challenging and requires a lot of effort to understand concepts. Good luck and any questions PM me :D

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4 years ago

The 1.53-kg uniform slender bar rotates freely about a horizontal axis through O. The system is released from rest when it is in

OlgaM077 [116]

Answer:

The spring constant = 104.82 N/m

The angular velocity of the bar when θ = 32° is 1.70 rad/s

Explanation:

From the diagram attached below; we use the conservation of energy to determine the spring constant by using to formula:

$T_1+V_1=T_2+V_2$

$0+0 = \frac{1}{2} k \delta^2 - \frac{mg (a+b) sin \ \theta }{2} \\ \\ k \delta^2 = mg (a+b) sin \ \theta \\ \\ k = \frac{mg(a+b) sin \ \theta }{\delta^2}$

Also;

$\delta = \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2}$

Thus;

$k = \frac{mg(a+b) sin \ \theta }{( \sqrt{h^2 +a^2 +2ah sin \ \theta} - \sqrt{h^2 +a^2})^2}$

where;

$\delta$ = deflection in the spring

k = spring constant

b = remaining length in the rod

m = mass of the slender bar

g = acceleration due to gravity

$k = \frac{(1.53*9.8)(0.6+0.2) sin \ 64 }{( \sqrt{0.6^2 +0.6^2 +2*0.6*0.6 sin \ 64} - \sqrt{0.6^2 +0.6^2})^2}$

$k = 104.82\ \ N/m$

Thus; the spring constant = 104.82 N/m

The angular velocity can be calculated by also using the conservation of energy;

$T_1+V_1 = T_3 +V_3 \\ \\ 0+0 = \frac{1}{2}I_o \omega_3^2+\frac{1}{2}k \delta^2 - \frac{mg(a+b)sin \theta }{2} \\ \\ \frac{1}{2} \frac{m(a+b)^2}{3} \omega_3^2 + \frac{1}{2} k \delta^2 - \frac{mg(a+b)sin \ \theta }{2} =0$