Answer:
162 kJ
Explanation:
The reaction given by the problem is:
- NBr₃(g) + 3 H₂O(g) → 3 HOBr(g) + NH₃(g) ∆H = +81 kJ
If we turn it around, we have:
- 3 HOBr(g) + NH₃(g) → NBr₃(g) + 3 H₂O(g) ∆H = -81 kJ
If we think now of HOBr and NH₃ as our reactants, then now we need to find out <u>which one will be the </u><em><u>limiting reactant</u></em> when we have 9 moles of HOBr and 2 moles of NH₃:
- When we have 1 mol NH₃, we need 3 mol HOBr. So when we have 2 moles NH₃, we need 6 moles HOBr. We have more than 6 moles HOBr so that's our <em>reactant in excess</em>, thus NH₃ is our limiting reactant.
-81 kJ is our energy change when there's one mol of NH₃ reacting, so we <u>multiply that value by two when there's two moles of NH₃ reacting</u>. The answer is 81*2 = 162 kJ.
Answer:
32.8g/mole
Explanation:
Given parameters:
Mass of sample of gas = 32.8g
Volume = 22.4L
Unknown:
Molecular weight = ?
Solution:
To solve this problem we must understand that at rtp;
1 mole of gas occupies a volume of 22.4L
Number of mole of the gas = 1 mole
Now;
Mass = number of moles x molecular weight
molecular weight =
=
= 32.8g/mole
Answer:
a) Br-, Kr, Sr2+
Explanation:
plus and minus sort of mean opposite here
Br has 35
Br- has 36
Sr has 38
Sr2+ has 36
Kr has 36
in which of the following sets do all species have the same number of electrons (isoelectronic)?
a) Br-, Kr, Sr2+
b) C, N3-, O2-
c) Mg2+, Sr2+, Ba2+
d) O, O2-, O2+
Mg2+ has 10
Sr2+ has 36
Ba2+ has 54
Br- has 36
Kr has 36
Sr2+ has 36
C has 6
N3- has 10
O2- has 10
O has 8
O2+ has 6
toppr
I’m going to go with The pH 1 solution is two times more acidic than that with a pH of 1. If that’s not the answer, then my second best guess would be The pH solution is ten times more acidic than that with a pH of 2.
The first and third answer choice wouldn’t even be an answer so you can just cancel those two out and pick between answer choice 2 or 4.
Hope this helps, and have an amazing day!! :))
The part with the highest frequency and shortest wavelength, you mean? That would be gamma rays.