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N76 [4]
3 years ago
13

In your own words explain the theory of plate tectonics, how earthquakes, mountain formation are related to plate tectonics.

Physics
2 answers:
AURORKA [14]3 years ago
3 0

Explanation:

The theory of plate tectonics states that the Earth's solid outer crust, the lithosphere, is separated into plates that move over the asthenosphere, the molten upper portion of the mantle. Oceanic and continental plates come together, spread apart, and interact at boundaries all over the planet

Monica [59]3 years ago
3 0

Answer:

The theory of plate tectonics can be best described as a large-scale motion of the plates making up the Earth's crust. Plate tectonics are related to earthquakes because of the fact that they are the cause for earthquakes. This happens when there is a fault (crack in earth's crust). When the plates that make up these faults slip, collide, or spread, this causes the plates to grind together which causes them to get stuck together and therefore they start building up pressure. When the pressure is too great, the plates break loose causing a huge amount of energy to be released, this causes the earth to move, which is a earthquake. Mountains form in much the same way, since the plates move to form them, and they are formed at the crust's boundaries when the plates push together so hard that they are pushed up along with stone and other materials. This causes bulges made of the plates to form, which are called mountains. All this movement is caused by plate tectonics since they all move in a large-scale, causing both earthquakes and mountains to form.

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4 years ago
An electron is accelerated from rest by a potential difference of (24.5 A) V for a distance of (4.50 B) cm. Determine the de Bro
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Answer:

206 pm

Explanation:

We are given that

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Distance,d=4.5+B cm

We have to determine the de Brogile wavelength of the electron.

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\Delta V=24.5+11=35.5 V

d=4.5+5=9.5 cm

Charge on electron,q =1.6\times 10^{-19} C

Mass of electron=m=9.1\times 10^{-31} kg

Speed of electron,v=\sqrt{\frac{2q\Delta V}{m}}

Using the formula

v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 35.5}{9.1\times 10^{-31}}

v=3.53\times 10^6 m/s

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