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larisa86 [58]
3 years ago
8

Please help me solve these!!!

Mathematics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

Maybe add or Multply every surface then add the surfaces then get your answer

Step-by-step explanation:

Maybe pay attention next time.

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Complete the square for x^2-8x and write as the square of a binomial.
tatuchka [14]
=x^2-8x+16-16
= (x-4) ^2-16
=[(x-4) -4][(x-4) +4]
=(x-8) x
6 0
3 years ago
Determine which consecutive integers do not have a real zero of between them. a. (–6, –5) c. (–2, –1) b. (–5, –4) d. (1, 2) Plea
svetoff [14.1K]
We have by the intermediate value theorem that if a continuous function takes values both above and below zero at 2 points, there is a zero of the function in-between. We have that polynomials are continues. Let's calculate f(-6) and f(-5). f(-6)=-36 while f(-5)=-1. Thus, we cannot conclude that there is a root between them.
F(-2)=8, f(-1)=-1, so there is a flip; a zero must exist between them.
F(1)=-1, f(2)=20, so again there is a change of signs.
f(-5)=-1, f(-4)=14 so there is a root still.
We have that the only choice that does not have a root between the integers is choice a.

7 0
3 years ago
Let event A = the place is a city let B = the place is in North America what is P(A and B)
frozen [14]

Answer:

  D. 2/7

Step-by-step explanation:

We assume that the intention is that one of the places is chosen at random from the list of 7 places.

2 of those are cities in North America, so the probability that a place randomly chosen from this list is a city in North America is ...

  P(A & B) = 2/7

6 0
3 years ago
Read 2 more answers
Fill in the missing fractions
konstantin123 [22]

Answer:

The second choice.

Step-by-step explanation:

1/5 = 20%

2/5 = 40%

3/4 = 75%

6 0
3 years ago
Read 2 more answers
Many variants of poker are played with both cards in players’ hands and shared community cards. Players’ hand are some combinati
Natalija [7]

Answer:

Step-by-step explanation:

Given that Anna has a flush, this means that the three shared cards and the 2 cards with Anna has the same suit, therefore given this condition the probability that Brad also has a flush is computed here as:

= Probability that Brad has the same suit cards as those shared cards and Anna

= Probability that Brad selected 2 cards from the 8 cards remaining of that suit

= Number of ways to select 2 cards from the 8 cards of that same suit / Total ways to select 2 cards from the remaining 47 cards

 = 0.0259

Therefore 0.0259 is the required probability here.

the little calculation is shown in the picture attached

5 0
3 years ago
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