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Ede4ka [16]
3 years ago
14

How much force is needed to accelerate a vehicle with a mass of 1000 kg at a rate of 5 m/s2?

Physics
1 answer:
Mashcka [7]3 years ago
8 0
The force needed to accelerate a vehicle with a mass of 1000kg at a rate of 5m/s2 would be 5000
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A car is traveling 35 mph on a smooth surface. If a balanced force is applied to the car, what happens?
zepelin [54]

Answer:

Here is the answer.

Explanation:

Balanced forces- they are those forces that produce 0 resultant forces.

therefore, on applying a balanced force on the object, it wouldn't result in any change, as resultant force would be 0.

7 0
4 years ago
In an inertia balance, a body supported against gravity executes simple harmonic oscillations in a horizontal plane under the ac
avanturin [10]

Answer:

2) f = 0.707 Hz

Explanation:

Given m₁ = 1.0 kg , f₁ = 1.0 Hz

So using the equation

f₁ = ( 1 / 2 π ) * √K / m₁

Solve to determine K' constant of spring

K = m * ( 4 π ² * f ² )

K = 1.0 kg * ( 4 π ² 1.0² Hz )

K = 39.4784176

So given 2.0 kg the frequency can be find using formula

f₂ = ( 1 / 2 π ) * √K / m₂

f₂ = ( 1 / 2 π ) * √39.4784176 / 2.0 kg

f₂ = 0.707 Hz

4 0
3 years ago
Are particularly useful in explaining deformation and strengthening in metallic materials.
vampirchik [111]

Answer: value

Explanation:

8 0
4 years ago
Please help meeeeeeeeeeeeeeeee
Julli [10]

I can't see the answers clearly, but I can see the question. So, I'll just give you a clue/hint.

A stars brightness actually depends on how far it is from your location. If it's far away, it will be dimmer than its counterpart that is closer. To summarize it, if two stars have the same brightness level and one is farther away than the other, the one farther away will appear dimmer than its closer counterpart.

5 0
3 years ago
A generator rotates at 95 Hz in a magnetic field of 0.025 T. It has 550 turns and produces an rms voltage of 170 V and an rms cu
weeeeeb [17]

Answer:

Peak current= 84.86 A

Area of each turn = 0.029 m^2

Explanation:

The peak value of current can be obtained from Irms= 0.707Io. Where Io is the peak current.

Hence;

Irms= 60.0A

Io= Irms/0.707

Io = 60.0/0.707

Io= 84.86 A

Vrms= 0.707Vo

Vo= Vrms/0.707= 170/0.707 = 240.45 V

From;

V0 = NABω

Where;

Vo= peak voltage

N= number of turns

B= magnetic field

A= area of each coil

ω= angular velocity

But ω= 2πf = 2×π×95= 596.9 rads-1

Substituting values;

A= Vo/NBω

A= 240.45/550×0.025×596.9

A= 0.029 m^2

6 0
4 years ago
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