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Tanya [424]
3 years ago
12

A mass of 10 kg is at a point A on the table. It moved to a point B. If the line joining A and B is horizontal. What is the work

done on the object by the gravitational force ? Explain your answer
Physics
1 answer:
elena55 [62]3 years ago
6 0

Answer:

Work done by gravitational force = 0 joule

Explanation:

Work done is given by the relation

                        W  =  F   x    S   joule

Where,    F  -  the force applied in the form of push or pull

               S  -  displacement caused by the force

If a force is acting on a body and it doesn't cause any displacement, then work done will be zero.

Gravitational force acts on the body even if the body is at rest.

<em>Work done by the gravitational is applicable only if there is some vertical component of motion involved.</em>

In this case, some amount of work is done to move the body from point A to B.But, the body is displaced in the horizontal direction. No vertical motion is involved.

So, the work done due to gravitational force on a mass is zero joule.

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Two identical conductors have charge -1.8 C and 5.5 C on them, respectively. They are connected by a conducting wire for a short
Aleks04 [339]

Answer: 1.85 C

Explanation:

Given

charges on the conductors are -1.8\ C and 5.5\ C

They are connected by a conducting wire for a short period of time and then disconnected. During this time charge flow from the wire and net charge becomes 5.5-1.8=3.7\ C

This charge will be equally distribute among the two conductors i.e. 1.85 C on each conductor.

5 0
3 years ago
Which of the following would reduce the resistance of a metal wire?
Marina CMI [18]
B. increasing the temperature
7 0
3 years ago
Read 2 more answers
Rank this objects in order of their acceleration small to larger
sp2606 [1]

Answer:

The answer is "DACB".

Explanation:

The missing data of the question is defined in the attached file please find it.

Using formula:

\to F= m \cdot a\\\\ \to m= 5 \ kg

In object A:

F= 15 \\\\a =\frac{F}{m} = \frac{15}{5} = 3

In object B:

F= 30 \\\\a =\frac{F}{m} = \frac{30}{5} = 6

In object C:

F= 20 \\\\a =\frac{F}{m} = \frac{20}{5} = 4

In object D:

F= 0 \\\\a =\frac{F}{m} = \frac{0}{5} = 30

That's why the answer is "DACB" .

6 0
2 years ago
why is it possible for the temperature of a system to remain constant even though heat is released or absorbed by the system?
Olegator [25]

Answer:

Isothermal Process

Explanation:

In this process heat is released or absorbed by the system happens at very slow rate in order to continually maintain the  temperature of the system through heat exchange. so ΔT = 0 ⇒ ΔU =0

First law of Thermodynamics ΔQ = ΔU + ΔW

⇒ ΔQ = ΔW

e.g Carnot Cycle

4 0
3 years ago
________ is a thermodynamic function that increases with the number of energetically equivalent ways to arrange components of a
ss7ja [257]

Answer:

entropy

Explanation:

5 0
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