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2 years ago

If jill and katie share 42 chocolates in the ratio of 3:4 then how may chocolates does jill get?

Mathematics

1 answer:

nasty-shy [4]2 years ago

5 0

Answer:

jil got 18 chocolates

Step-by-step explanation:

let the ratio constants be x,

so, jil has 3x chocolates

katie has 4x chocolates

and we know total chocolates = 42

then,

=》3x + 4x = 42

=》7x = 42

=》x = 42 ÷ 7

=》x = 6

so, jil got 3x = (3 × 6) = 18 chocolates

katie got 4x = (4 × 6) = 24 chocolates

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2 years ago

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Step-by-step explanation:

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2 years ago

On Aaron’s farm, 1/10 of the animals are cows, ⅖ of the animals are chickens,

Ray Of Light [21]

Answer:

There are 5 pigs on Aaron's farm

Step-by-step explanation:

1. Start with 40 animals

2. 1/10 of the animals are cows, so divide 40 by 10 and you will find that 4 of the animals are cows

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3 years ago

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2

Basile [38]

Answer:

$f(x) = x^3 - 2x^2 -3x + 6$

Step-by-step explanation:

According to the Factor Theorem, if (x - k) is a factor of a polynomial P(x), then P(k) must equal zero.

We are given that a polynomial function has the zeros 2, √3, and -√3. So, we can let k = 2, √3, -√3.

So, according to the Factor Theorem, P(2), P(√3) and P(-√3) must equal 0.

Testing each choice, we can see that only A is true:

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Testing all three values yields that:

$\displaystyle \begin{aligned} f(2) &= (2)^3 - 2(2)^2 -3(2) + 6 \\ &= (8) - (8) -(6) + (6) \\ &= 0\stackrel{\checkmark}{=}0 \\ \displaystyle f(\sqrt{3}) &= (\sqrt{3})^3 - 2(\sqrt{3})^2 - 3(\sqrt{3}) + 6 \\ &=(3\sqrt{3}) -(6)-(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \\ f(-\sqrt{3}) &= (-\sqrt{3})^3 - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 \\ &=(-3\sqrt{3}) -(6)+(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \end{aligned}$

Hence, our answer is A.

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