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liq [111]
2 years ago
5

Triangle abc is similar to triangle def solve for both unknown sides

Mathematics
1 answer:
Serhud [2]2 years ago
7 0

Given:

Triangles ABC and DEF are similar triangles.

AB = 6 m, BC = 16 m, CA = 15 m, DE = x, EF = 32 m, FD = y

To find:

The values of unknown sides, i.e., x and y.

Solution:

We know that the corresponding parts of similar triangles are proportional and triangles ABC and DEF are similar triangles, so

\dfrac{AB}{DE}=\dfrac{BC}{EF}=\dfrac{CA}{FD}

\dfrac{6}{x}=\dfrac{16}{32}=\dfrac{15}{y}

\dfrac{6}{x}=\dfrac{1}{2}=\dfrac{15}{y}

Now,

\dfrac{6}{x}=\dfrac{1}{2}

6\times 2=1\times x

12=x

Similarly,

\dfrac{1}{2}=\dfrac{15}{y}

1\times y=15\times 2

y=30

Therefore, the measure of unknown sides are x = 12 m and y = 30 m.

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"write an expression that evaluates to true if the value of the integer variable x is divisible (with no remainder) by the integ
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x= y* q + m, i.e when an integer x is divided by y gives quotient q and remainder m.

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3 years ago
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PLEASE HELP ASAP!!
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Answer:

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Step-by-step explanation:

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The repair cost of a Subaru engine is normally distributed with a mean of $5,850 and a standard deviation of $1,125. Random samp
Yuri [45]

Answer:

C. $5180

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Z-scores lower than -2 or higher than 2 are considered unusual.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random normally distributed variable X, with mean \mu and standard deviation \sigma, the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5850, \sigma = 1125, n = 20, s = \frac{1125}{\sqrt{20}} = 251.56

Which of the following mean costs would be considered unusual?

We have to find the z-score for each of them

A. $6350

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{6350 - 5850}{251.56}

Z = 1.99

Not unusual

B. $6180

Z = \frac{X - \mu}{s}

Z = \frac{6180 - 5850}{251.56}

Z = 1.31

Not unusual

C. $5180

Z = \frac{X - \mu}{s}

Z = \frac{5180 - 5850}{251.56}

Z = -2.66

Unusual, and this is the answer.

3 0
3 years ago
Raymond bought 3/4 of dozen rolls. How many rolls did he buy?
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Hey there! A dozen rolls = 12 rolls, of means multiply, we are going to multipy 3/4 by 12, make 12 a fraction, 12=12/1. Now, we can multiply 3/4 by 12/1. 3/4×12/1=36/4. Simplify 36/4 to 9. So, Raymond bought 9 rolls.
6 0
3 years ago
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