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malfutka [58]
3 years ago
11

Were the continents once joined together as a supercontinent? Give 3 pieces of evidence to support Alfred Wegeners Theory of Con

tinental Drift.
Physics
2 answers:
exis [7]3 years ago
8 0

Answer:

I dont know tbh

Explanation:

sattari [20]3 years ago
5 0
Yes! Fossils, The outlines of the continents and geological features .
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The equation for photosynthesis is 6H2O (water) + 6CO2 (carbon dioxide) + Light Energy → C6H12O6 (glucose) + 6O2 (oxygen). When
aleksklad [387]

Answer:

b

Explanation:

bc

8 0
3 years ago
How should the magnetic field lines be drawn for the magnets shown below?
sergeinik [125]

 Option B is the correct answer that show how magnetic field lines should be drawn for the magnets shown in the figure.

<h3>What is Magnetic Line of Force ?</h3>

The Magnetic Line of Force of a magnet is defined as the line along which a free N - pole would tend to move if placed in the field of a line such that the tangent to it at any point gives the direction of the field at that point.

When the two unlike poles are placed to each other, there will be attraction. And when the two like poles are placed to each other, there will be repulsion. The reason is that the line of force tend to move from the north pole to the south pole.

From the given diagram, the two magnets are of the same south pole. They are of like pole and there will be repulsion between the two magnets.

Therefore, Option B is the correct answer that show how magnetic field lines should be drawn for the magnets shown in the figure.

Learn more about Magnetic Field Lines here:  brainly.com/question/17011493

#SPJ1

5 0
2 years ago
A rock is dropped from a helght of 2.5 meters. What is its velocity when it reaches the ground?
Nataly_w [17]

u=0 m/s

h=2.5m

Using kinematic eq:

{v}^{2}  -  {u}^{2}  = 2gh \\  {v}^{2}  -  {0}^{2}  = 2gh \\ v =  \sqrt{2gh}  \\ v =  \sqrt{2 \times 10 \times 2.5}  \\ v =  \sqrt{50}  \\ v = 7.07m/s

7 0
3 years ago
A horizontal 649 N merry-go-round of radius 1.05 m is started from rest by a constant horizontal force of 61.3 N applied tangent
nexus9112 [7]

Answer:

The kinetic energy of the merry-go-round is 632.82 J

Explanation:

Given;

weight of the merry-go-round, W = 649 N

radius of the merry-go-round, r = 1.05 m

applied horizontal force, F =  61.3 N

acceleration due to gravity, g = 9.8 m/s²

mass of  merry-go-round, m = W/g

                                               = 649/9.8  = 66.225 kg

moment of inertia of merry-go-round, I = ¹/₂mr²

                                                                 = ¹/₂ x 66.225 x (1.05)²

                                                                 = 36.507 kg.m²

Angular acceleration of the merry-go-round, α

τ = Iα = Fr

α = Fr / I

Where;

α is angular acceleration

α = (61.3 x 1.05) / 36.507

α = 1.763 rad/s²

Angular velocity of the merry-go-round, ω

ω = αt

ω = 1.763 x 3.34

ω = 5.888 rad/s

Finally, the kinetic energy of the merry-go-round, K.E

K.E = ¹/₂Iω²

K.E = ¹/₂ x 36.507 x (5.888)²

K.E = 632.82 J

4 0
3 years ago
How can a simple machine lift a heavy load with smaller effort​
solniwko [45]

Answer:

The axle is fixed to a frame or a block. The pulley is normally fixed to a support above the load. The load is tied to one end of the rope and the effort is applied at the other end. Such a pulley makes our work easier by simply changing the direction of the force, i.e. a load is lifted up using a downward effort.

May be this will help U

6 0
3 years ago
Read 2 more answers
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