How must a force be applied to cause resonance?

Explain how sedimentary rock is formed.

Klio2033 [76]

Answer:

They are formed on or near the Earth’s surface from the compression of ocean sediments or other processes.

Explanation:

8 0

3 years ago

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A long, rigid conductor, lying along an x axis, carries a current of 4.99 A in the negative x direction. A magnetic field is pre

Tcecarenko [31]

Answer with Explanation:

We are given that

Current in conductor=I=4.99 A (-x direction)

Magnetic field=B= $3.72\hat{i}+8.72x^2\hat{j}mT=(3.72i+8.72x^2j)\times 10^{-3}$

(1mT= $10^{-3} T$ )

x(in m) and B (in mT)

Length of conductor is given in negative x- direction

$\vec{L}=-x\hat{i}$

$dL=-dx\hat{i}$

Force on current carrying conductor is given by

$F=I(L\times B)$

$dF=I(dL\times B)$

Integrating on both sides then we get

$\vec{F}=\int_{1.41}^{2.77}(4.99)(-dx\hat{i}\times (3.72\hat{i}+8.72x^2\hat{j}))\times 10^{-3}$

$\vec{F}=-\int_{1.41}^{2.77}(4.99\times 10^{-3})\cdot 8.72(x^2\hat{k})dx$ ( $i\times i=0, i\times j=k$

$\vec{F}=-(4.99\times 10^{-3}\times 8.72)[\frac{x^3\hat{k}}{3}]^{2.77}_{1.41}$

$\vec{F}=-\frac{(4.99\times 10^{-3}\cdot 8.72)}{3}((2.77)^3-(1.41)^3)\hat{k}$

$\vec{F}=-0.268 \hat{k} N$

a. x- component of force=0

b.y- component of force=0

c.z- component of force=-0.268 N

5 0

3 years ago

choose a substance you're familiar with. what are its physical and chemical properties? How would you measure its density? What

Artist 52 [7]

You can look at magnesium, it can react with oxygen to form oxides. (chemical) it is malleable and a solid at room temperature. (physical)

to measure its density, the mass and volume can be worked out and from this density too. look up the equation, it is quite easy :)

physical changes -- it can be melted, and oxidized

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4 years ago

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A student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.

Umnica [9.8K]

The catch in this one is: We don't know how much force the student used to push the bike.

It wasn't necessarily the 100N. That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium. The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push. That's what's so great about wheels ! That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel". I looked at it, I turned it over and I looked on all sides. I thought it was too simple. I didn't know then it was elegant. I threw him out. I was so dumb. I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ? Stay tuned:

-- The bike covered 15 meters in 5 seconds. Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

Power = 36.73 watts

7 0

3 years ago

Describe and give an example of the doppler effect

Alexxandr [17]

The Doppler effect is when the frequency of a sound changes as the position of you and the sound changes. For example, if a fire truck comes at you, the siren sound will increase, then, after it passes you, then the sound will decrease. The thing that just happened is the Doppler effect!

Have a nice day! :)

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3 years ago

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