= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)
= -0.00225 m
New length = L + ΔL
= 1.25 m + (-0.00225 m)
= 1.248
D
Answer:
Magnitude of resultant = 131.15
Direction of resultant = 3.97°
Explanation:
||u|| = 70
θ = 40°
||v|| = 85
θ = 335°
Resultant
Magnitude of resultant = 131.15
Direction of resultant = 3.97°
Answer:
The heat is 115478.4 J.
Explanation:
Given that,
Mass of water = 0.400 kg
Power = 200 W
Suppose, we determine how much heat must be added to the water to raise its temperature from 20.0°C to 89.0°C?
We need to calculate the heat
Using formula of heat
Where, m = mass of water
c = specific heat
Put the value into the formula
Hence, The heat is 115478.4 J.