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4 years ago

What and where are muscles attached

Physics

2 answers:

Rudiy274 years ago

8 0

Answer:

arms, legs mostly everywhere, how do you move?

koban [17]4 years ago

6 0

Idk lol this is so tough I don’t know lol

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The dancing bear family loves when their trainer gives them little treats to reward them for a good performance. If the trainer

lions [1.4K]

Answer:

748 treats.

Explanation:

If the trainer gives out 34 treats and gave them out for 22 shows, then to find the total you need to multiply 34 by 22, or (a longer but more simple way) add 34, 22 times.

5 0

3 years ago

A 45-mH inductor is connected in series with a 60-Ω resistor through a 15-V dc power supply and a switch. If the switch is close

egoroff_w [7]

Answer:

The current is 0.248 A

Explanation:

Given that,

Inductor $L= 45\times10^{3}\ H$

Resistance $R= 60\Omega$

Voltage = 15 volt

Time $t =7.0\times10^{-3}\ sec$

We need to calculate the current

Using formula of current

$I=\dfrac{V}{R}(1-e^{\dfrac{-R}{L}}t)$

Where, V = voltage

R = resistance

L = inductance

T = time

Put the value into the formula

$I=\dfrac{15}{60}(1-e^{\dfrac{-60}{45\times10^{3}}}\times7\times10^{-3})$

$I=0.248\ A$

Hence, The current is 0.248 A.

4 0

3 years ago

A potential difference of 18 V is applied to a resistor whose resistance is 240 Ω . What is the current that flows through the r

leonid [27]

Answer:

0.075A

Explanation:

V = IR

where V - voltage, I - current, R - resistance

Hence, 18 = I * 240

I = 18/240

I = 0.075A

6 0

3 years ago

Read 2 more answers

g You heard the sound of a distant explosion (3.50 A/10) seconds after you saw it happen. If the temperature of the air is (15.0

Soloha48 [4]

Answer:

The answer is "1557 meters".

Explanation:

speed of sound in ( $\frac{m}{s}$ ) $= 331.5 + 0.60 \ T^{\circ}\ C\\\\$

$\to V = 331.5 + 0.6 \times 24 = 346 \frac{m}{s}\\\\\to t = 4.5 \ seconds \\\\\to S = vt = 346 \times 4.5 = 1557 \ meters$

8 0

3 years ago

A car accelerates from 14 m/s to 21m/s in 6.0 s. What was its acceleration? How far did it travel in this time? Assume constant

MrMuchimi

Explanation:

It is given that,

Initial velocity of the car, u = 14 m/s

Final velocity of the car, v = 21 m/s

Time taken, t = 6 s

Acceleration of the car is equal to the change in speed divided by time i.e. it can be written as :

$a=\dfrac{v-u}{t}$

$a=\dfrac{21\ m/s-14\ m/s}{6\ s}$

a = 1.166 m/s²

a = 1.17 m/s²

For finding how fat it travel in this time is calculated using third equation of motion :

$v^2-u^2=2as$

s = distance

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{21^2-14^2}{2\times 1.17}$

s = 104.7 m

Hence, the acceleration of the car is 1.166 m/s² and distance covered by it is 104.7 m

7 0

4 years ago

Read 2 more answers