Answer:
2.57 g of H₂
Solution:
The Balance Chemical Equation is as follow,
N₂ + 3 H₂ → 2 NH₃
According to Balance equation,
34.06 g (2 moles) NH₃ is produced by = 6.04 g (3 moles) of H₂
So,
14.51 g of NH₃ will be produced by = X g of H₂
Solving for X,
X = (14.51 g × 6.04 g) ÷ 34.06 g
X = 2.57 g of H₂
One mole of NaCl weighs 58.44 grams
Therefore 1L of one mole of NaCl contains 58.44 grams
1L of 0.2m NaCl contains 58.44x0.2 = 11.69grams
300mL of 0.2m NaCl contains 11.69x0.3 = 3.51 grams
Answer:
1. People can get rid of hiccups by holding their breath 2. Going outside with wet hair will cause a cold 3. People should not swim right after eating
Explanation:
When the salt AgI dissolves in water it dissociates as follows;
AgI ---> Ag⁺ + I⁻
molar solubility is the number of moles that are dissolved in 1 L of solution.
If molar solubility of AgI is x, then molar solubility of Ag⁺ is x and I⁻ is x.
the formula for solubility product constant - ksp of AgI is given below
ksp = [Ag⁺][I⁻]
ksp = (x)(x)
ksp = 8.51 x 10⁻¹⁷
therefore,
x² = 8.51 x 10⁻¹⁷
x = 9.22 x 10⁻⁹
since molar solubility of AgI is x, then molar solubility of AgI is 9.22 x 10⁻⁹ M