Answer:
E = 1.602v
Explanation:
Use the Nernst Equation => E(non-std) = E⁰(std) – (0.0592/n)logQc …
Zn⁰(s) => Zn⁺²(aq) + 2 eˉ
2Ag⁺(aq) + 2eˉ=> 2Ag⁰(s)
_____________________________
Zn⁰(s) + 2Ag⁺(aq) => Zn⁺²(aq) + 2Ag(s)
Given E⁰ = 1.562v
Qc = [Zn⁺²(aq)]/[Ag⁺]² = (1 x 10ˉ³)/(0.150)² = 0.044
E = E⁰ -(0.0592/n)logQc = 1.562v – (0.0592/2)log(0.044) = 1.602v
Answer:
not valid
Explanation:
Expert judgment is a useful validation method to verify the reliability of an investigation that is defined as “an informed opinion of people with experience in the subject, who are recognized by others as qualified experts in it, and who can give information, evidence, judgments and assessments ”
After submitting an instrument for comparison to the consultation and expert opinion, it must meet two quality criteria: validity and reliability. The validity of content is often established based on two situations, one that concerns the design of a test and the other, the validation of an instrument subject to translation and standardization procedures to adapt it to different cultural meanings. It is here that the task of the expert becomes a fundamental task to eliminate irrelevant aspects, incorporate those that are essential and / or modify those that require it.
Cant really explain, for say, but its D.-ide
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Answer:- There are
moles.
Solution:- It is a unit conversion problem where we are asked to convert mg of aspartame to moles. Aspartame is
and it's molar mass is 294.31 grams per mole.
mg are converted to grams and then the grams are converted to moles as:
![1.00mg Aspartame(\frac{1g}{1000mg})(\frac{1mole}{294.31g})](https://tex.z-dn.net/?f=1.00mg%20Aspartame%28%5Cfrac%7B1g%7D%7B1000mg%7D%29%28%5Cfrac%7B1mole%7D%7B294.31g%7D%29)
=
moles of aspartame
So, there would be
moles of aspartame in 1.00 mg of it.
The answer is false because it goes in a full 360 degree circle