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3 years ago

PLZ HELP ON TIMER WILL GIVE BRAINLIEST

Chemistry

1 answer:

sergeinik [125]3 years ago

3 0

Answer:

I would put the final answer choice: "Scientists must first develop certain technologies before missions can be completed"

Explanation:

The first option is partially true, but we have ways around it.

The second option is straight-up false.

The third option doesn't make much sense, how can one work with technology that will be developed in the future and doesn't yet exist?

Therefore, the fourth option is the best.

Hope this helps

-cyber

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Explain with the help of examples difference between elements and compounds

djyliett [7]

Answer:

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3 years ago

Property Of acids Helpp

Mandarinka [93]

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3 years ago

The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan

Alex17521 [72]

Answer : The rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $701K$ = $2.57M^{-1}s^{-1}$

$K_2$ = rate constant at $525K$ = ?

$Ea$ = activation energy for the reaction = $1.5\times 10^2kJ/mol=1.5\times 10^5J/mol$

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 701 K

$T_2$ = final temperature = 525 K

Now put all the given values in this formula, we get:

$\log (\frac{K_2}{2.57M^{-1}s^{-1}})=\frac{1.5\times 10^5J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{701K}-\frac{1}{525K}]$

$K_2=0.0606M^{-1}s^{-1}$

Therefore, the rate constant at 525 K is, $0.0606M^{-1}s^{-1}$

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3 years ago

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 496g of bromine liquid is produced

vfiekz [6]

Answer:

6.208 mol

Explanation:

Mass of Bromine Liquid = 496g

Number of moles = ?

Relationship between number of moles and mass is given as;

Number of moles = Mass / Molar mass

Molar mass of Bromine = 79.9g

Number of moles = 496 / 79.9 = 6.208 mol

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3 years ago

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3 years ago

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