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Vikentia [17]
3 years ago
7

PLEASE HELP DUE TODAY 55 POINTS

Chemistry
2 answers:
olga_2 [115]3 years ago
5 0

Answer:

volume of gas will be, 26.3 mL

Explanation:

Dvinal [7]3 years ago
3 0

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

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Unabbreviated electron configuration of magnesium
fenix001 [56]

Answer:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

Explanation:

Abbreviated and unabbreviated electronic configuration:

The abbreviated electronic configuration uses the noble gas configuration i.e complete electronic shells. For example, the atomic number of neon is ten and magnesium is twelve. The abbreviated electronic configuration of magnesium is written by using the neon abbreviation in following way:

The electronic configuration of neon is given below:

Ne₁₀ = 1s² 2s² 2p⁶

The abbreviated electronic configuration of magnesium:

Mg₁₂ = [Ne] 3s²

While the unabbreviated electronic configuration is written without using noble gas electronic configuration.

Unabbreviated electronic configuration of magnesium:

Mg₁₂ = 1s² 2s² 2p⁶ 3s²

5 0
3 years ago
How much energy is required to heat a frozen can of juice (360 grams- mostly water) from 0 degrees Celsius ( the temperature of
Usimov [2.4K]

Answer:

1,100,160J or 262.94 kcal

Explanation:

The juice is frozen at 0 degrees Celsius and I assume that it will become gas at 100 degrees Celsius. So we change the form of the water from solid to liquid, then to gas. That means we have to find out how much heat needed to change water form too, not only the heat needed to increase its temperature.

The latent heat of water is 4.2J/g °C while the heat of fusion is 334 J/g and the heat of vaporization is 2260 J/g. The energy needed will be:

360g * 4.2J/g °C * (110-0°C ) + 360g * 334 J/g + 360g * 2260 /g = 1,100,160J or 262.94 kcal.

8 0
3 years ago
GUYS I NEED HELP THIS IS DUE TONIGHT !!!
kenny6666 [7]

Explanation:

To balance the reactions given, we must understand that the principle to follow is the law of conservation of matter.

Based on this premise, the number of moles of species on the reactant and product side must be the same;

 

      Li   +   Br₂  →    LiBr

Put a,b and c as the coefficient of each species

   aLi  + bBr₂ → cLiBr

balancing Li;

       a  = c

 balancing Br;

        2b  = c

 let a  = 1;

       c  = 1

        b = \frac{1}{2}  

or a = 2, b = 1 , c = 2

        2Li   +   Br₂  →    2LiBr

        P   +   Cl₂  →    PCl₃

Using the same method;

      aP  + bCl₂ → cPCl₃

balancing P;

          a  = c

balancing Cl;

          2b  = 3c

let a = 1;

     c  = 1

      b  = \frac{3}{2}

 or

  a  = 2, b  = 3, c  = 2

    2P   +   3Cl₂  →    2PCl₃

iii,

   H₂   +   SO₂  →   H₂S   +   H₂O

use coefficients a,b,c and d;

    aH₂   +   bSO₂  →   cH₂S   +   dH₂O

balancing H;

    2a = 2c + 2d

balancing S;

     b  = c

balancing O

    2b  = d

 let b  = 1,

      c = 1

       d  = 2

    a  = 3

    3H₂   +   SO₂  →   H₂S   +   2H₂O

3 0
3 years ago
Vhat are some of the benefits and drawbacks of recycling?​
Eva8 [605]

Answer:

benefits: can help reduce waste in land fills, and promotes reusability (turned into different products)

drawbacks: can be much more expensive to salvage than to just throw it in a landfill, and most of the time products cannot be recycled effectively due to its material.

5 0
3 years ago
For the following reaction, 22.9 grams of nitrogen monoxide are allowed to react with 5.80 grams of hydrogen gas. nitrogen monox
ololo11 [35]

Answer:

1) Maximun ammount of nitrogen gas: m_{N2}=10.682 g N_2

2) Limiting reagent: NO

3) Ammount of excess reagent: m_{N2}=4.274 g

Explanation:

<u>The reaction </u>

2 NO (g) + 2 H_2 (g) \longrightarrow N_2 (g) + 2 H_2O (g)

Moles of nitrogen monoxide

Molecular weight: M_{NO}=30 g/mol

n_{NO}=\frac{m_{NO}}{M_{NO}}

n_{NO}=\frac{22.9 g}{30 g/mol}=0.763 mol

Moles of hydrogen

Molecular weight: M_{H2}=2 g/mol

n_{H2}=\frac{m_{H2}}{M_{H2}}

n_{H2}=\frac{.5.8 g}{2 g/mol}=2.9 mol

Mol rate of H2 and NO is 1:1 => hydrogen gas is in excess

1) <u>Maximun ammount of nitrogen gas</u> => when all NO reacted

m_{N2}=0.763 mol NO* \frac{1 mol N_2}{2 mol NO}*\frac{28 g N_2}{mol N_2}

m_{N2}=10.682 g N_2

2) <u>Limiting reagent</u>: NO

3) <u>Ammount of excess reagent</u>:

m_{N2}=(2.9 mol - 0.763 mol NO* \frac{1 mol H_2}{1 mol NO})*\frac{2 g H_2}{mol H_2}

m_{N2}=4.274 g

8 0
3 years ago
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