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Vikentia [17]
3 years ago
7

PLEASE HELP DUE TODAY 55 POINTS

Chemistry
2 answers:
olga_2 [115]3 years ago
5 0

Answer:

volume of gas will be, 26.3 mL

Explanation:

Dvinal [7]3 years ago
3 0

Answer : The final volume of gas will be, 26.3 mL

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 0.974 atm

P_2 = final pressure of gas = 0.993 atm

V_1 = initial volume of gas = 27.5 mL

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 22.0^oC=273+22.0=295K

T_2 = final temperature of gas = 15.0^oC=273+15.0=288K

Now put all the given values in the above equation, we get:

\frac{0.974 atm\times 27.5 mL}{295K}=\frac{0.993 atm\times V_2}{288K}

V_2=26.3mL

Therefore, the final volume of gas will be, 26.3 mL

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2 years ago
Can someone solve this for me I'm confused.
Artemon [7]

Answer:

310.53 g of Cu.

Explanation:

The balanced equation for the reaction is given below:

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Next, we shall determine the mass of CuSO₄ that reacted and the mass Cu produced from the balanced equation. This can be obtained as follow:

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Summary:

From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

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From the balanced equation above,

159.5 g of CuSO₄ reacted to produce 63.5 g of Cu.

Therefore, 780 g of CuSO₄ will react to produce = (780 × 63.5)/159.5 = 310.53 g of Cu.

Thus, 310.53 g of Cu were obtained from the reaction.

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