Answer:
The height in which the book is dropped from is 1.28 m.
Explanation:
Mass of the book, m = 1.5 kg
initial velocity of the book, u = 0
final velocity of the bok, v = 5 m/s
The height in which the book is dropped from is given by;
v² = u² + 2gh
v² = 0 + 2gh
v² = 2gh
h = v² / 2g
h = (5)² / (2 x 9.8)
h = 1.28 m
Therefore, the height in which the book is dropped from is 1.28 m.
Solution is given in following attachment.
Answer:
Explanation:
Impulse results in a change of momentum
FΔt = mΔV
F = mΔV/Δt
The impulse acting on the hammer will equal the impulse acting on the nail
If we assume upward is the positive direction
F = m(vf - vi)/t
F = 1.2(1.0 - (-1.5)) / 0.001
F = 3000 N