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inn [45]
3 years ago
15

When your teacher drops a 1.5kg book from rest, it speeds up as it falls down suppose that book hits the ground at a speed of 5m

/s what hight was it dropped from
Physics
1 answer:
Kamila [148]3 years ago
7 0

Answer:

The height in which the book is dropped from is 1.28 m.

Explanation:

Mass of the book, m = 1.5 kg

initial velocity of the book, u = 0

final velocity of the bok, v = 5 m/s

The height in which the book is dropped from is given by;

v² = u² + 2gh

v² = 0 + 2gh

v² = 2gh

h = v² / 2g

h = (5)² / (2 x 9.8)

h = 1.28 m

Therefore, the height in which the book is dropped from is 1.28 m.

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Answer:

0\:\mathrm{ m/s^2}

Explanation:

Recall the formula for acceleration:

\displaystyle\\a=\frac{v_f-v_i}{\Delta t}, where v_f is final velocity, v_i is initial velocity, and \Delta t is elapsed time (change in velocity over this amount of time).

Let's look at our time vs velocity graph. At t=0 seconds, V=25 m/s. So her initial velocity is 25 m/s.

We want to find the acceleration during the first 5 seconds of motion. Well, looking at our graph, at t=5 seconds, isn't our velocity still 25 m/s? Therefore, final velocity is 25 m/s (for this period of 5 seconds).

We are only looking from t=0 seconds to t=5 seconds which is a total period of 5 seconds. Therefore, elapsed time is 5 seconds.

Substituting values in our formula, we have:

\displaystyle a=\frac{25-25}{5}=\frac{0}{5}=\boxed{0\:\mathrm{m/s^2}}

Alternative:

Without even worrying about plugging in numbers, let's think about what acceleration actually is! Acceleration is the change in velocity over a certain period of time. If we are not changing our velocity at all, we aren't accelerating! In the graph, we can see that we have a straight line from t=0 seconds to t=5 seconds, the interval we are worried about. This indicates that our velocity is staying the same! At t=0 seconds, we have a velocity of 25 m/s and that velocity stays the same until t=5 seconds. Even though we are moving, we haven't changed velocity, which means our average acceleration is zero!

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2 years ago
What is the number of significant digits in the measurement 34.000 m?
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The answer is d.5 your welcome
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A skateboarder with a mass of 60 kg moves with a force of 20 N. What is her acceleration?
Zanzabum

Explanation:

Solution,

  • Mass(m)= 60 kg
  • Force (F)= 20 N
  • Acceleration (a)= ?

We know that,

  • F=ma
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So, her acceleration is 0.333 m/s².

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Answer:

a = g = 9.81[m/s^2]

Explanation:

This problem can be solve using the second law of Newton.

We know that the forces acting over the skydiver are only his weight, and it is equal to the product of the mass by the acceleration.

m*g = m*a

where:

g = gravity = 9.81[m/s^2]

a = acceleration [m/s^2]

Note: If the skydiver will be under air resistance forces his acceleration will be different.

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