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inn [45]
3 years ago
15

When your teacher drops a 1.5kg book from rest, it speeds up as it falls down suppose that book hits the ground at a speed of 5m

/s what hight was it dropped from
Physics
1 answer:
Kamila [148]3 years ago
7 0

Answer:

The height in which the book is dropped from is 1.28 m.

Explanation:

Mass of the book, m = 1.5 kg

initial velocity of the book, u = 0

final velocity of the bok, v = 5 m/s

The height in which the book is dropped from is given by;

v² = u² + 2gh

v² = 0 + 2gh

v² = 2gh

h = v² / 2g

h = (5)² / (2 x 9.8)

h = 1.28 m

Therefore, the height in which the book is dropped from is 1.28 m.

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An electron is placed on a line connecting two fixed point charges of equal charge but the opposite sign. The distance between t
viktelen [127]

Answer:

a)    F_net = 6.48 10⁻¹⁸ ( \frac{1}{x^2} + \frac{1}{(0.300-x)^2} ),   b) x = 0.15 m

Explanation:

a) In this problem we use that the electric force is a vector, that charges of different signs attract and charges of the same sign repel.

The electric force is given by Coulomb's law

         F =k \frac{q_2q_2}{r^2}

         

Since when we have the two negative charges they repel each other and when we fear one negative and the other positive attract each other, the forces point towards the same side, which is why they must be added.

          F_net= ∑ F = F₁ + F₂

let's locate a reference system in the load that is on the left side, the distances are

left side - electron       r₁ = x

right side -electron     r₂ = d-x

let's call the charge of the electron (q) and the fixed charge that has equal magnitude Q

we substitute

          F_net = k q Q  ( \frac{1}{r_1^2}+ \frac{1}{r_2^2})

          F _net = kqQ  ( \frac{1}{x^2} + \frac{1}{(d-x)^2} )

         

let's substitute the values

          F_net = 9 10⁹  1.6 10⁻¹⁹ 4.50 10⁻⁹ ( \frac{1}{x^2} + \frac{1}{(0.30-x)^2} )

          F_net = 6.48 10⁻¹⁸ ( \frac{1}{x^2} + \frac{1}{(0.300-x)^2} )

now we can substitute the value of x from 0.05 m to 0.25 m, the easiest way to do this is in a spreadsheet, in the table the values ​​of the distance (x) and the net force are given

x (m)        F (N)

0.05        27.0 10-16

0.10          8.10 10-16

0.15          5.76 10-16

0.20         8.10 10-16

0.25        27.0 10-16

b) in the adjoint we can see a graph of the force against the distance, it can be seen that it has the shape of a parabola with a minimum close to x = 0.15 m

4 0
3 years ago
Raising the temperature of a gas will increase its pressure to<br> volume of the gas would do what
joja [24]

Answer: Boyle found that when the pressure of a gas at a constant temperature is increased, the volume of the gas decreases. When the pressure of a gas is decreased, the volume increases. This relationship between pressure and volume it's called Boyle's law.

Explanation: In the 1600s, Boyle measured the volumes of gases at different pressures. Boyle found that when the pressure of a gas at a constant temperature is increased, the volume of the gas decreases. When the pressure of a gas is decreased, the volume increases. This relationship between pressure and volume it's called Boyle's law.

3 0
2 years ago
Why might some people not have believed Galileo's discoveries?
Mademuasel [1]
They did not believed Galileo's discoveries because religiouse reasons the preast said that all the bible is true but Galileo despised it.
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Why do the four outer planets have lower density than the four inner planets?
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Because the four outer planets are comprised of mostly gases give me a thanks or brainiest answer if this helps! 
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